|
|
Sponsored Content
Top Forums
Shell Programming and Scripting
Snytax error on If Statement--help
Post 302192792 by dannyd_y on Wednesday 7th of May 2008 09:58:29 PM
05-07-2008
Snytax error on If Statement--help
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if [ $day = 0 ] ; then
$day=31
fi
2);;
if [ $day = 0 ] ; then
if [ `expr $year % 4` -eq 0]; then
$day = 28
else
$day = 29
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day
cp $HOME/*$DATE*.log $HOME/QVGLog
cd $HOME/QVGLog
gzip *
the error message is
./call: line 9: syntax error near unexpected token `('
./call: line 9: `if($day =7 ); then'
Pls help, i've checked the syntax for if else statement on web, but cant fix it.
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if [ $day = 0 ] ; then
$day=31
fi
2);;
if [ $day = 0 ] ; then
if [ `expr $year % 4` -eq 0]; then
$day = 28
else
$day = 29
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day
cp $HOME/*$DATE*.log $HOME/QVGLog
cd $HOME/QVGLog
gzip *
the error message is
./call: line 9: syntax error near unexpected token `('
./call: line 9: `if($day =7 ); then'
Pls help, i've checked the syntax for if else statement on web, but cant fix it.
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hello,
I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.
if ; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi
the above code just displays
please let me know... (2 Replies)
Discussion started by: rakeshou
2 Replies
2. Shell Programming and Scripting
:b:hi,
I have a script as given below:
pr_det="1"
if
then
awk ' BEGIN {printf("%23s","session")}' >> report.txt
awk ' BEGIN {printf "\n"} ' >> report.txt
else
awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt
awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
Discussion started by: jisha
1 Replies
3. Linux
Hi ,
I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this
if
then
VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 `
echo " VW_$VW_VAR "
sed -e... (16 Replies)
Discussion started by: capri_drm
16 Replies
4. Shell Programming and Scripting
HI i am getting error while executing the given statement
for filename in `cat a/file.lst`
do
if then
echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log
exit
else
count1=`awk 'END {print NR}' $filename`
echo "$count1">>a.log
count2=`awk 'END {print... (4 Replies)
Discussion started by: ravi214u
4 Replies
5. Shell Programming and Scripting
hi,
When i try to run the code below, i get the following error
"ksh: syntax error: `(' unexpected"
i am not able to figure it out. Can anyone help me?
Code: (2 Replies)
Discussion started by: ragavhere
2 Replies
6. UNIX for Dummies Questions & Answers
Hi,
This is my script to catch any oracle errors.
In this, the $sqlerr returns
ORA-01017: invalid username/password; logon denied
when i specify wrong username/password
the if condition is failing. how can i resolve the issue.
the if statement gives error
sqloutput=`sqlplus -s -L... (1 Reply)
Discussion started by: Swapna173
1 Replies
7. Shell Programming and Scripting
I am working on script for stale nfs.
the file consists of
cat data01stale.log
- - - - /abcd/backup
- - - - /abcd/data
Script (16 Replies)
Discussion started by: nareshkumar522
16 Replies
8. Shell Programming and Scripting
Hi
Can you please tell me what is wrong with this line:
if && ]; then
basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error. (7 Replies)
Discussion started by: rtagarra
7 Replies
9. Shell Programming and Scripting
Can anybody tell the correct way to use the following awk pattern check within an if statement?
When I run this command outside of the if statement
cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group"
I get the following... (0 Replies)
Discussion started by: kieranfoley
0 Replies
10. UNIX for Beginners Questions & Answers
hello all
im new to unix and when i use below script i get an error :
#! /bin/bash
Echo -e "enter the name of the file : \c"
read file_name
if
then
echo "$file_name found"
else
echo "$file_name not found"
fi
running the script i get below error :
$ ./hello (26 Replies)
Discussion started by: Ibrahims1
26 Replies
LEARN ABOUT SUSE
holidays
holidays(4) File Formats holidays(4) NAME
holidays - prime/nonprime table for the accounting system SYNOPSIS
/etc/acct/holidays DESCRIPTION
The /etc/acct/holidays file describes which hours are considered prime time and which days are holidays. Holidays and weekends are con- sidered non-prime time hours. /etc/acct/holidays is used by the accounting system. All lines beginning with an "*" are comments. The /etc/acct/holidays file consists of two sections. The first non-comment line defines the current year and the start time of prime and non-prime time hours, in the form: current_year prime_start non_prime_start The remaining non-comment lines define the holidays in the form: month/day company_holiday Of these two fields, only the month/day is actually used by the accounting system programs. The /etc/acct/holidays file must be updated each year. EXAMPLES
Example 1: Example of the /etc/acct/holidays file. The following is an example of the /etc/acct/holidays file: * Prime/Nonprime Table for the accounting system * * Curr Prime Non-Prime * Year Start Start * 1991 0830 1800 * * only the first column (month/day) is significant. * * month/day Company Holiday * 1/1 New Years Day 5/30 Memorial Day 7/4 Indep. Day 9/5 Labor Day 11/24 Thanksgiving Day 11/25 day after Thanksgiving 12/25 Christmas 12/26 day after Christmas SEE ALSO
acct(1M) SunOS 5.10 28 Mar 1991 holidays(4)