...
basically i need to list all the contents in all files in all directories (starting from root and then onwards)...i will get the session saved in a file (just a secure CRT, etc)
...
Regards,
If you need the names of each file to prepend to the content's file in the final output file, use the following code ( slower than the previous one ) :
Hi
I have 2 questions:
Q1 - What does
${1:+$1/}*
mean? I guess it lists all files in current directory - Could any one explain how this expression works?
Q2 - I am trying to list directories only in current path - I know that ls could be used but I thought I'd give find a try. I need to... (5 Replies)
Please provide me a shell script so that i can list which file or directory has been deleted, by which user and at what time. The script should take date as argument and should list out name of the file/directory, which user had deleted them and at what time since that particular date. Kindly post. (1 Reply)
Hi,
Simple question.
If i could find a file been listed in many dirctories, how to get the unique list of directories.
find / -name "abc*" --> will give me list of directories.
/home/abc.txt
/home/ddd/abcd.txt
/home/ddd/abcde/txt
So how to get
/home
/home/ddd
Thanks in... (2 Replies)
Hi
When im listing (ls -al ) its listing directories without / at the end of directories
dir1 dir2 dir3
and i need to list directories with
dir1/ dir2/ dir3/ and this should not be made by command ls -F
/ should be embedded at the last
since one of the scripts reads directories... (1 Reply)
I'm looking for a script which outputs the list of directories and sub directories from root level consisting of specific files. For instance I want shell script to list all the directories and subdirectories containing .txt files.:wall: (4 Replies)
Hello all!
I'm looking to list directories and sub-directories of a path, on this forum I found this command:
find $path -type d -exec ls -ld {} \;
The issue I have is that with a simple ls, the list is listed by name, and using -t I get it by time.
How could I list directories and sub... (5 Replies)
How can I find and print the directories on a server that have more than 5,000 files? There's some spam emails and I'm trying to find all directories that have a lot of spam
The file count should just be the files directly under that directory, not like the total from all nested directories
... (1 Reply)
Discussion started by: vanessafan99
1 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)