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Full Discussion: Grep date from ls -l
Top Forums Shell Programming and Scripting Grep date from ls -l Post 302191205 by GenMen on Thursday 1st of May 2008 09:50:48 PM
Old 05-01-2008
Grep date from ls -l
I have a script which required the month and day as the input

ex : ./script <Month> <date>

from this I get the list of files to do further logics. The problem is when I assign these $1 and $2 to variables, and use grep command in the script

ls -l |grep "$1 $2"

it works fine for two digit dates, but for single digit dates, it doesnt work as Unix leaves an additional space in the ls -l list..

How can get this done.
 

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LEARN ABOUT HPUX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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