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Top Forums Shell Programming and Scripting [Unix] a dos style rename wont work Post 302187142 by era on Saturday 19th of April 2008 02:24:18 PM
Old 04-19-2008
You are using $1 but the loop variable is $file. So your loop loops over the files and puts the name of each in $file, but you are not referring to that variable, you are referring to another variable which continues to point to the first file in the list. Try changing the $1:s to $file:s.
 

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explain_rename_or_die(3)				     Library Functions Manual					  explain_rename_or_die(3)

NAME
explain_rename_or_die - change the name of a file and report errors SYNOPSIS
#include <libexplain/rename.h> void explain_rename_or_die(const char *oldpath, const char *newpath); DESCRIPTION
The explain_rename_or_die function is used to call the rename(2) system call. On failure an explanation will be printed to stderr, obtained from explain_rename(3), and then the process terminates by calling exit(EXIT_FAILURE). This function is intended to be used in a fashion similar to the following example: explain_rename_or_die(oldpath, newpath); oldpath The oldpath, exactly as to be passed to the rename(2) system call. newpath The newpath, exactly as to be passed to the rename(2) system call. Returns: This function only returns on success. On failure, prints an explanation and exits. SEE ALSO
rename(2) change the name or location of a file explain_rename(3) explain rename(2) errors exit(2) terminate the calling process COPYRIGHT
libexplain version 0.52 Copyright (C) 2008 Peter Miller explain_rename_or_die(3)
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