I'd still use a case statement, because I think it's easier. This gets a bit obscure, though.
This is not entirely robust in the face of random user input (if they give : as "year" it doesn't work right) but I guess you might be coping with that already earlier in your script.
One reason to prefer case over if is that you don't have to worry about an empty argument string; there are various tricks like if [ X"$input" = X ] but they're rather unsightly IMHO.
In my ksh script, if the conditions of a if statement are true, then do nothing; otherwise, execute some commands.
How do I write the "do nothing" statement in the following example?
Example:
if (( "$x"="1" && "$y"="a" && "$z"="happy" ))
then
do nothing
else
command
command
fi... (3 Replies)
Hi All,
I am using Unix ksh script.
I need to insert values to a table using the o/p from a slelect statement.
Can anybody Help!
My script looks like tihs.
---`sqlplus -s username/password@SID << EOF
set heading off
set feedback off
set pages 0
insert into ${TB_NAME}_D... (2 Replies)
I can't find anything wrong with this line of code, it works when there is one file in the directory but more than one i get a "too many arguements2 error
if ; then
am i missing something? (3 Replies)
Hello friends,
I have a boubt passing different arguments at a time for any one option in below code.
I would also like to check which option has been selected (any one of i, r, u ) so that whether or not matching argument passed can be verified.
for i and r - install and re-install -... (4 Replies)
I am writing a script in bash and want to perform the operation
I check number of arguments and make a print statement with the passes arguments
If I pass 3 arguments I will do
printf "$frmt" "$1" "$2" "$3"If I have 4 arguments I do
printf "$frmt" "$1" "$2" "$3" "$4"etc (4 Replies)
Hi
Am pretty new to C..
Am trying to pass the arguments from command line and use them in switch case statement..
i have tried the following
#include <stdlib.h>
main(int argc, char* argv)
{
int num=0;
if ( argc == 2 )
num = argv;
printf("%d is the num value",num);
switch ( num )
... (2 Replies)
Hello,
I have a question regarding the usage statement of a script.
I have 2 parameters "--pto" and "--pto_list". To start the script I will need one of them. Both together are not possible.
How this would be printed out within a usage statement?
My suggestion would be:
Usage:... (4 Replies)
Hi folks,
I have a scenario to convert the update statements into insert statements using shell script (awk, sed...) or in database using regex.
I have a bunch of update statements with all columns in a file which I need to convert into insert statements.
UPDATE TABLE_A SET COL1=1 WHERE... (0 Replies)
I'm stuck on a particular problem and need some guidance. I have a file with a name and a phone number in it (teledir.txt). I need to do a $# in a separate script to take a positional parameter and check to see if it is in the file. To quote the question:
If one argument is supplied, check... (6 Replies)
Discussion started by: Eric7giants
6 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)