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Top Forums Shell Programming and Scripting if statement - how can I do 2 arguments? Post 302184802 by era on Sunday 13th of April 2008 05:21:25 AM
Old 04-13-2008
Sounds like you want

Code:
if [ $# = 0 ]; then
  echo no arguments
elif [ $# = 1 ]; then
  echo one argument "$1"
else ...

Personally I'd prefer case over if for this but that's more of a stylistic issue.
 

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POW(3)									 1								    POW(3)

pow - Exponential expression

SYNOPSIS
number pow (number $base, number $exp) DESCRIPTION
Returns $base raised to the power of $exp. Note In PHP 5.6 onwards, you may prefer to use the ** operator. PARAMETERS
o $base - The base to use o $exp - The exponent RETURN VALUES
$base raised to the power of $exp. If both arguments are non-negative integers and the result can be represented as an integer, the result will be returned with integer type, otherwise it will be returned as a float. EXAMPLES
Example #1 Some examples of pow(3) <?php var_dump(pow(2, 8)); // int(256) echo pow(-1, 20); // 1 echo pow(0, 0); // 1 echo pow(-1, 5.5); // PHP >4.0.6 NAN echo pow(-1, 5.5); // PHP <=4.0.6 1.#IND ?> NOTES
Note This function will convert all input to a number, even non-scalar values, which could lead to weird results. SEE ALSO
exp(3), sqrt(3), bcpow(3), gmp_pow(3). PHP Documentation Group POW(3)
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