Sponsored Content
Top Forums Shell Programming and Scripting passing asterisk to a script as variable Post 302180939 by rubin on Tuesday 1st of April 2008 02:01:50 PM
Old 04-01-2008
As previously stated in an ssh script, the commands ( and eventually all the special characters in them, for example: *, $, ...) will be evaluated first by the current shell, before ssh-in.

So you need to properly escape all of them. For more check these threads:


https://www.unix.com/shell-programmin...s-via-ssh.html

https://www.unix.com/shell-programmin...sh-script.html

-
 

10 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

Passing a variable into an awk script

Hello all, I'm trying to run a script of this format - for i in $(cat <file>); do grep $i <file1>|awk '{print $i, $1, $2}' It's not working - does anyone know how this can be done? Khoom (5 Replies)
Discussion started by: Khoomfire
5 Replies

2. UNIX for Dummies Questions & Answers

passing variable to my script

Hello everybody: Im trying to run the following script on my sol9 machine: line='' ((lineCount= 0)) export lineCount more /tmp/MSISDNs | wc -l > /tmp/tmp cat /tmp/tmp | read lineCount export lineCount; while (( lineCount > 0 )) do line= tail -$lineCount... (5 Replies)
Discussion started by: aladdin
5 Replies

3. Shell Programming and Scripting

How to ignore * (asterisk) in a variable

I am using a shell script to read SQL statements stored in a DB2 table and write them out to a file. The problem I have is that some SQL statements have an "*" in them which gets resolved as the list of files in the current directory when I run the script. How can I prevent the "*" from being... (7 Replies)
Discussion started by: bradtri2
7 Replies

4. Shell Programming and Scripting

Passing asterisk As A Parameter

I have written a Shell Script Program which accepts 3 parameters as shown below: ./calc 20 + 2 in the above line ./calc is the Shell Script itself with 3 parameters, namely: 20 + and 2. Well, now let's look inside the Script: result=$1$2$3 echo $result The output will be as... (8 Replies)
Discussion started by: indiansoil
8 Replies

5. Shell Programming and Scripting

How to assign * asterisk to variable?

How can I assign asterisk to variable I have try a="\* " but I was not succesful :( any idea ? thanks (5 Replies)
Discussion started by: kvok
5 Replies

6. Shell Programming and Scripting

Passing variable from shell script to python script

I have a shell script main.sh which inturn call the python script ofdm.py, I want to pass two variables from shell script to python script for its execution. How do i achieve this ????? Eg: main.sh a=3 b=3; c= a+b exec python ofdm.py ofdm.py d=c+a Thanks in Anticipation (4 Replies)
Discussion started by: shashi792
4 Replies

7. Shell Programming and Scripting

help passing variable from script

Hello, How can I pass a variable into a 2nd file? I'm running a script: ls -la $1 >pem99 cat pem99 | awk '{ print $3}' >us99 cat us99 | read us98 This then tells me the owner of a file. my second file is: echo OWNER GROUP OTHERS echo echo --data-- $us98 ... (2 Replies)
Discussion started by: Grueben
2 Replies

8. Shell Programming and Scripting

Passing variable as an argument to another script

Hi, I am trying to pass a variable as an argument to another script. While substitution of variable, I am facing a problem. varaiable "a" value should be -b "FPT MAIN". When we pass "a" to another script, we are expecing it to get substitue as ./test.sh -b "FPT MAIN". But, it is getting... (9 Replies)
Discussion started by: Manasa Pradeep
9 Replies

9. Shell Programming and Scripting

Need to use asterisk in variable

Hi All, I am having a challange to pass the asterisk in the variable. Basically, I am writing a shell script to check if a marker file exists but when I am assigning the varialbe it cannot use the wildcard asterisk as expected, therefore, my program is always outputs "Marker file is not... (4 Replies)
Discussion started by: express14
4 Replies

10. Shell Programming and Scripting

Passing variable from called script to the caller script

Hi all, Warm regards! I am in a difficult situation here. I have been trying to create a shell script which calls another shell script inside. Here is a simplified version of the same. Calling Script. #!/bin/ksh # want to run as a different process... (6 Replies)
Discussion started by: LoneRanger
6 Replies
SSH-COPY-ID(1)						      General Commands Manual						    SSH-COPY-ID(1)

NAME
ssh-copy-id - install your public key in a remote machine's authorized_keys SYNOPSIS
ssh-copy-id [-i [identity_file]] [user@]machine DESCRIPTION
ssh-copy-id is a script that uses ssh to log into a remote machine and append the indicated identity file to that machine's ~/.ssh/autho- rized_keys file. If the -i option is given then the identity file (defaults to ~/.ssh/id_rsa.pub) is used, regardless of whether there are any keys in your ssh-agent. Otherwise, if this: ssh-add -L provides any output, it uses that in preference to the identity file. If the -i option is used, or the ssh-add produced no output, then it uses the contents of the identity file. Once it has one or more fin- gerprints (by whatever means) it uses ssh to append them to ~/.ssh/authorized_keys on the remote machine (creating the file, and directory, if necessary.) NOTES
This program does not modify the permissions of any pre-existing files or directories. Therefore, if the remote sshd has StrictModes set in its configuration, then the user's home, ~/.ssh folder, and ~/.ssh/authorized_keys file may need to have group writability disabled manu- ally, e.g. via chmod go-w ~ ~/.ssh ~/.ssh/authorized_keys on the remote machine. SEE ALSO
ssh(1), ssh-agent(1), sshd(8) OpenSSH 14 November 1999 SSH-COPY-ID(1)
All times are GMT -4. The time now is 08:32 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy