03-28-2008
Hi Curleb,
Thanks for replying. I think I found out what was happening. I read somehwere else that a script is called from another script a new shell is opened and the variables are set up for that second shell (or child shell) and once the script is executed the shell is closed and with it all the variables. So if I want to execute the script in the current shell I have to use the option . ./script_name.sh (with the dot and space) and at Exit 0 the previous shell disappears and the child shell stays as current. This is my intepretation of what I read, I'm sure there is more professional explanation for it
Thanks for your help
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MAKESH(1) General Commands Manual MAKESH(1)
NAME
makeSH - a .SH script maker
SYNOPSIS
makeSH files
DESCRIPTION
MakeSH examines one or more scripts and produces a .SH file that, when run under sh, will produce the original script. The .SH script so
produced has two sections containing code destined for the output. The first section has variable substitutions performed on it (taking
values from config.sh), while the second section does not. MakeSH does not know which variables you want to have substituted, so it puts
the whole script into the second section. It's up to you to insert any variable substitutions in the first section for any values you want
from config.sh.
You should run makeSH from within your top-level directory and use the relative path to the file as an argument, so that the "Extracting
..." line printed while running the produced .SH file later on will give that same path.
AUTHOR
Larry Wall <lwall@netlabs.com>
SEE ALSO
pat(1), metaconfig(1), makedist(1).
BUGS
It could assume that variables from metaconfig's Glossary need to be initialized in the first section, but I'm too lazy to make it do that.
LOCAL MAKESH(1)