cat setting variables

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# 1  
Old 09-10-2002
cat setting variables

hi All
I have a file that has 4 lines:
1. yesterday's date (mm/dd/yyyy)
2. yesterday's day- dd
3. yesterday's month- mm
4. yesterday's year- yyyy

I want to read this file and place them in variables. how can I do this.

Please help.

thanks in advance!!

# 2  
Old 09-10-2002
you can try a for loop.
# 3  
Old 09-10-2002
Question HOW?

I want the lines to be placed in seperate variables... could you kind enough to provide me with the commands?

# 4  
Old 09-10-2002
man not much thought goes into your reply so not much goes into mine. heh

well in perl you can do it this way.

#! /usr/bin/perl -w


open FILE, "$FILE" or die "NO GO ($!)";

foreach (<FILE>) { chomp; push @contents, $_; };
foreach (@contents) { print $_,"\n" };

each element of the array contents has a line of the file

$contents[0] has "mm/dd/yyyy"
$contents[1] has "dd"
$contents[2] has "mm"
$contents[3] has "yyyy"

to do it in shell scripting

#! /bin/ksh


for line in `cat test.file`;do
        if [ $i == 1 ]; then
        elif [ $i == 2 ]; then
        elif [ $i == 3 ]; then
        elif [ $i == 4 ]; then
echo VAR1=$var1
echo VAR2=$var2
echo VAR3=$var3
echo VAR4=$var4

both scripts are under the assumption that the file contains the following data


Last edited by Optimus_P; 09-10-2002 at 12:32 PM..
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