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Top Forums UNIX for Dummies Questions & Answers sed question Post 302175522 by orahi001 on Friday 14th of March 2008 09:15:39 AM
Old 03-14-2008
sed question

How would I use sed to print everything on the line after the regular expresion?

I have a configuration file setting several variables.

cfg.dat
DDB = cpptest
SUDBNAME = sucpptestdb
host = cpptest

Example
I want to search for the regular expresion 'SUDBNAME =' and print everything on the line after it


Expected output:
sucpptestdb


thanks
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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