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Full Discussion: How to grep / zgrep to output ONLY the matching filename and line number?
Top Forums UNIX for Dummies Questions & Answers How to grep / zgrep to output ONLY the matching filename and line number? Post 302174938 by keelba on Wednesday 12th of March 2008 04:21:01 PM
Old 03-12-2008
I would try something like this:

#!/usr/bin/ksh
for i in `ls *.txt`
do
grep "<STRING>" $i 1>/dev/null 2>&1
if [[ $? = 0 ]]
then
echo -n "${i}: "
grep -n "<STRING>" $i | awk -F: '{printf "%s",$1" "}'
fi
done
echo
 

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LEARN ABOUT NETBSD

zegrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD
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