Hi,
I have a file, which is having a pattern "SEARCH" somewhere towards end of the file,
if i am giving " grep -i "SEARCH" $File" , it is taking too much time as file is very big.
So i want to search for the pattern from the back side of the file, how can we search for a pattern in bottom... (5 Replies)
hi,
I have looked at many grep threads and am unable to find something like this: please help.
I have a file which is generated from a report generator and i am trying to load a whole lot of specific data into a table for the users. One field is causing me problems.All the rest i can manage.... (7 Replies)
Hi Folks
I need a one liner to parse through a log and if the string is found print the line above, the line with the string and the line below.
example:
The ball is green and blue
Billy through the ball higer.
Jane got hurt with the ball.
So if I search for Billy I would need the 3... (1 Reply)
How to remove x lines form top and y lines form bottom.
This works, but like awk only cat file | head -n-y | awk 'NR>(x-1)'
so remove last 3 lines and 5 firstcat file | head -n-3 | awk 'NR>4' (5 Replies)
Oracle Linux 6.4
In a directory I have more than 300 files with the extension .log
I want the first 5 and last 5 lines of these .log files to be printed on screen with each file's name.
Expected output :
Printing first 5 and last 5 lines of FX_WT_Feb8_2014.log
!! Authentication... (7 Replies)
Hello forum,
Seems that only I have alot of questions regarding Ubuntu :D
In Ubuntu 12.04 LTS the gnome I have been using gdm and lightdm.
In lightdm the top and side bars are aka "unity" and can be removed using apt-get remove unity
I need to do the same for menu bars gdm. I do not... (0 Replies)
Hi,
i have a file which contains PID and wanted to execute kill command. but the thing is, when killing PID's needs to kill PID from bottom to top.
Please help
INPUT
21414 sh -c extract.ksh ASA
21416 /bin/ksh extract.ksh ASA
21428 /usr/bin/perl -w /var/tmp/tempperl.21416 ASA... (4 Replies)
Dear All
I was wondering if someone could help me in resolving an issue.
I have a file like this:
column1 column2
2 4
3 5
8 9
0 12
0 0
0 0
9 0
87 0
1 0
1 0
1 0
4 0 (2 Replies)
Hi,
I have a requirement where I need to delete given number of top and bottom rows in a flat file which has new line as its delimiter.
For ex: if top_rows=2 & bottom_rows=1
Then in a given file which looks like:
New York
DC
LA
London
Tokyo
Prague
Paris
Bombay
Sydney... (7 Replies)
Discussion started by: calredd
7 Replies
LEARN ABOUT OPENDARWIN
expr
EXPR(1) BSD General Commands Manual EXPR(1)NAME
expr -- evaluate expression
SYNOPSIS
expr expression
DESCRIPTION
The expr utility evaluates expression and writes the result on standard output.
All operators are separate arguments to the expr utility. Characters special to the command interpreter must be escaped.
Operators are listed below in order of increasing precedence. Operators with equal precedence are grouped within { } symbols.
expr1 | expr2
Returns the evaluation of expr1 if it is neither an empty string nor zero; otherwise, returns the evaluation of expr2.
expr1 & expr2
Returns the evaluation of expr1 if neither expression evaluates to an empty string or zero; otherwise, returns zero.
expr1 {=, >, >=, <, <=, !=} expr2
Returns the results of integer comparison if both arguments are integers; otherwise, returns the results of string comparison using
the locale-specific collation sequence. The result of each comparison is 1 if the specified relation is true, or 0 if the relation
is false.
expr1 {+, -} expr2
Returns the results of addition or subtraction of integer-valued arguments.
expr1 {*, /, %} expr2
Returns the results of multiplication, integer division, or remainder of integer-valued arguments.
expr1 : expr2
The ``:'' operator matches expr1 against expr2, which must be a regular expression. The regular expression is anchored to the begin-
ning of the string with an implicit ``^''. expr expects "basic" regular expressions, see re_format(7) for more information on regu-
lar expressions.
If the match succeeds and the pattern contains at least one regular expression subexpression ``(...)'', the string corresponding to
``1'' is returned; otherwise the matching operator returns the number of characters matched. If the match fails and the pattern
contains a regular expression subexpression the null string is returned; otherwise 0.
Parentheses are used for grouping in the usual manner.
EXAMPLES
1. The following example adds one to the variable a.
a=`expr $a + 1`
2. The following example returns the filename portion of a pathname stored in variable a. The // characters act to eliminate ambiguity
with the division operator.
expr //$a : '.*/(.*)'
3. The following example returns the number of characters in variable a.
expr $a : '.*'
DIAGNOSTICS
The expr utility exits with one of the following values:
0 the expression is neither an empty string nor 0.
1 the expression is an empty string or 0.
2 the expression is invalid.
STANDARDS
The expr utility conforms to IEEE Std 1003.2 (``POSIX.2'').
BSD July 3, 1993 BSD