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Full Discussion: unexpected pipeline result with find -exec
Top Forums Shell Programming and Scripting unexpected pipeline result with find -exec Post 302169157 by blued on Wednesday 20th of February 2008 12:42:59 PM
Old 02-20-2008
Thanks for the reply. "2001" is only a place holder.

If I only wanted to add something to the filename
Code:
find . -name *.sh -exec mv {} {}.add_something \;

would work anyway.
But I wanted to process the filename; using xargs seem to suffer a similar limitation: the replacement string can't be fed into $(sed ...) or another way of processing.

Code:
find . -name "*.cpp" | xargs -I name mv name $(echo name|sed -e s/old/new/g)

In this case the string name will be fed unprocessed into sed instead of the xarg replacement.

Thanks,
best,
blued
 

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LEARN ABOUT LINUX

zegrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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