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Full Discussion: remove part of a line
Top Forums Shell Programming and Scripting remove part of a line Post 302164804 by shamrock on Wednesday 6th of February 2008 01:27:31 AM
Old 02-06-2008
Quote:
Originally Posted by tiger99
Hi All
Thank you all for your help. I am using cut, because it's easier to understand for me


I have an issue with grep before pipe the result to get the $$.. removed.

I have
grep ".proc" file.txt | cut ....

From my understanding, it should only return lines with .proc
However, I am not getting how come the following line also gets returned?

/vobs/aw/database/proc/Account$$/main

Can someone help me, how can I modify my grep so that only something like a.proc or b.proc get returned ?

Thanks
That's because the "." stands for any character and grep matches it to the slash that comes before proc (/proc). To match "." escape it so that it loses its special meaning...

Code:
grep "\.proc" file.txt | cut

 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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