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Top Forums UNIX for Dummies Questions & Answers Any simple method to check date format (YYDDD)? Post 302154868 by vino on Wednesday 2nd of January 2008 08:18:36 AM
Old 01-02-2008
Quote:
Originally Posted by ganapati
Hi Guru's,

Are there any simple method to check the date format which is in "YYDDD"
(ex: 08002 for 02-Jan-2008)?

Eventhough this can be implemented in several way's, I need the simpler one. Any idea would be much appreciated.

Thanks in advance,
Mysore Ganapati
08366 will be greater than 08100 which will be greater than 08001.

You can use a simple -gt construct.

Code:
if [[ $ldate -gt $rdate ]] ; then
  echo "$ldate is greater is than $rdate"
fi ;

 

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rdate(1M)						  System Administration Commands						 rdate(1M)

NAME
rdate - set system date from a remote host SYNOPSIS
rdate hostname DESCRIPTION
rdate sets the local date and time from the hostname given as an argument. You must have the authorization solaris.system.date on the local system. Typically, rdate is used in a startup script. The inetd daemon responds to rdate requests. To enable inetd response, the lines invoking the time command in inetd.conf must not be com- mented out. USAGE
The rdate command is IPv6-enabled. See ip6(7P). ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWrcmdc | +-----------------------------+-----------------------------+ SEE ALSO
inetd(1M), inetd.conf(4), attributes(5), ip6(7P) SunOS 5.10 15 Feb 2001 rdate(1M)
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