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Top Forums UNIX for Dummies Questions & Answers Help in modulus operator in Bash Post 302148917 by spoown on Tuesday 4th of December 2007 06:13:23 AM
Old 12-04-2007
I don't think so ! You should perhaps use the expr command to do some basic mathematical command, but only with integer ! You can use it in a bash script !
 

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BCPOWMOD(3)								 1							       BCPOWMOD(3)

bcpowmod - Raise an arbitrary precision number to another, reduced by a specified modulus

SYNOPSIS
string bcpowmod (string $left_operand, string $right_operand, string $modulus, [int $scale = int]) DESCRIPTION
Use the fast-exponentiation method to raise $left_operand to the power $right_operand with respect to the modulus $modulus. PARAMETERS
o $left_operand - The left operand, as a string. o $right_operand - The right operand, as a string. o $modulus - The modulus, as a string. o $ scale -This optional parameter is used to set the number of digits after the decimal place in the result. You can also set the global default scale for all functions by using bcscale(3). RETURN VALUES
Returns the result as a string, or NULL if $modulus is 0. NOTES
Note Because this method uses the modulus operation, numbers which are not positive integers may give unexpected results. EXAMPLES
The following two statements are functionally identical. The bcpowmod(3) version however, executes in less time and can accept larger parameters. <?php $a = bcpowmod($x, $y, $mod); $b = bcmod(bcpow($x, $y), $mod); // $a and $b are equal to each other. ?> SEE ALSO
bcpow(3), bcmod(3). PHP Documentation Group BCPOWMOD(3)
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