How to make a function friend to both base and derived class
Hi,
I have a base class and derived a class from the base class, i want to print & read the data for the object created for the derived class,so i have overloaded both the << and >> operators and also have done the foward declaration.
Below is the code snippet,
Am using g++ and on compiling i get the below errors, how to fix this
Thanks
Nagarajan G
Need help on making a loop script base on what is inside a file...
File to read: List.txt
List.txt contains below w/c are file name as well:
SAMPLEa
SAMPLEb
SAMPLEc
SAMPLEd
SAMPLEe
SAMPLEf
.
.
.
Want to make a loop that will manipulate those that are inside the file.txt w/c are... (3 Replies)
Please help check an old code:
#include <iostream>
using namespace std;
template <class C>
class List {
//Linked list of C.
template<class U>
friend class ListItr;
private:
class ListEl {
public:
C val;
ListEl* next;
ListEl(const C& s, ListEl* n) : val(s) { next = n;}
};... (0 Replies)
Hi friends,
The derived class cannot access the base class's variables in my program. You can have a look at my code, I am actually using class templates.
#include <iostream>
using namespace std;
template <class T>
class Sum
{
friend void Check(Sum &s, T a, T b)
{
T x,... (2 Replies)
Hi,
Can anyone tell me why the following program is giving compiler error when I use a friend function of a class as the comparison predicate for the third parameter of std::sort() algorithm? How to correct it, keep the 'friend' intact?
#include <iostream>
#include <vector>
#include <list>... (1 Reply)
I have the two class definition as follows.
class A { public: int a; };
class B : virtual public A{ };
The size of class A is shown as 4, and size of class B is shown as 16. Why is this effect ?. (2 Replies)
Hello All,
I am a learner in C++. I was testing my inheritance knowledge with following piece of code.
#include <iostream>
using namespace std;
class base
{
public :
void display()
{
cout << "In base display()" << endl;
}
void display(int k)
{... (2 Replies)
Dear All,
I have a requests to retrieve all lines if second line last columns meets certain criteria.
Here is the output of the result
Table: DSSBDW.DA_MASK_CLK_AR
120908 0 86 86 - 1934528 0 70 100 -*-
Table: DSSBDW.DA_MASK_CLK_IP
310657 22030 143 185 - 5281169 7 88 77 *-*
Table:... (5 Replies)
Discussion started by: ckwan123
5 Replies
LEARN ABOUT X11R4
iostream
FBB::IOStream(3bobcat) std::istream and std::ostream FBB::IOStream(3bobcat)NAME
FBB::IOStream - Combines std::istream and std::ostream features
SYNOPSIS
#include <bobcat/iostream>
Linking option: -lbobcat
DESCRIPTION
This class combines the features of the std::istream and std::ostream classes. The std::istream and std::ostream may be physically differ-
ent streams. FBB:IOStream objects may, e.g., be associated with streams wrapped around pipes (see, e.g., FBB::IfdStream and FBB::OFd-
Stream), to construct bi-directional pipes.
NAMESPACE
FBB
All constructors, members, operators and manipulators, mentioned in this man-page, are defined in the namespace FBB.
INHERITS FROM
FBB::IOStreambuf (private inheritance),
std::istream,
std::ostream
CONSTRUCTORS
o IOStream():
The default constructor constructs an empty FBB::IOStream objects. It should not be used before its open member (see below) was
called.
o IOStream(std::istream &in, std::ostream &out):
This constructor associates the IOStream object with a std::istream and a std::ostream. All output operations will be passed on to
the std::ostream, all input operations to the std::istream. The streams passed to IOStream should outlive the IOStream object. This
constructor performs the actions of the default constructor and then calls the IOStream::open member De copy constructor is avail-
able as well.
MEMBER FUNCTIONS
All members of std::istream and std::ostream are available, as FBB::IOStream inherits from these classes. Furthermore, when switching
between std::istream and std::ostream operations, no intermediate seekg() or seekp() operation will normally be required, since the base
classes will normally be associated with physically different streams.
o void open(std::istream &in, std::ostream &out):
This member (re)associates the IOStream object with a std::istream and a std::ostream. All output operations will be passed on to
the std::ostream, all input operations to the std::istream. The streams passed to IOStream() should outlive the IOStream object. If
this member is called for an IOStream object already associated with an std::ostream object, the already associated std::ostream
object is flushed before setting up the new association.
o void clear():
This member clears the error states of the associated std::istream and std::ostream objects.
EXAMPLE
See the example provided with process(3bobcat).
FILES
bobcat/iostream - defines the class interface
SEE ALSO bobcat(7), ifdstream(3bobcat), iostreambuf(3bobcat), ofdstream(3bobcat), process(3bobcat)BUGS
None Reported.
DISTRIBUTION FILES
o bobcat_3.01.00-x.dsc: detached signature;
o bobcat_3.01.00-x.tar.gz: source archive;
o bobcat_3.01.00-x_i386.changes: change log;
o libbobcat1_3.01.00-x_*.deb: debian package holding the libraries;
o libbobcat1-dev_3.01.00-x_*.deb: debian package holding the libraries, headers and manual pages;
o http://sourceforge.net/projects/bobcat: public archive location;
BOBCAT
Bobcat is an acronym of `Brokken's Own Base Classes And Templates'.
COPYRIGHT
This is free software, distributed under the terms of the GNU General Public License (GPL).
AUTHOR
Frank B. Brokken (f.b.brokken@rug.nl).
libbobcat1-dev_3.01.00-x.tar.gz 2005-2012 FBB::IOStream(3bobcat)