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Top Forums Programming How to make a function friend to both base and derived class Post 302146334 by ennstate on Tuesday 20th of November 2007 03:24:00 AM
Old 11-20-2007
How to make a function friend to both base and derived class

Hi,
I have a base class and derived a class from the base class, i want to print & read the data for the object created for the derived class,so i have overloaded both the << and >> operators and also have done the foward declaration.

Below is the code snippet,
Code:
#include <iostream>

class Line; // Forward Declaration for friend

class Point {
 private:
   int x,y;
 public:
   virtual void draw() ;
   friend std::ostream& operator<< ( std::ostream& , const Line&);
   friend std::istream& operator>> ( std::istream& ,  Line&);
};


class Line : public Point {
 private:
  int color;
 public :
   void draw () { std::cout<< "Drawing a Line" << std::endl; }
   friend std::ostream& operator<< ( std::ostream& , const Line&);
   friend std::istream& operator>> ( std::istream& ,  Line&);
};

inline
std::ostream& operator<< ( std::ostream &os , const Line &out ) {
  os<<"Line: [" << out.x << "," << out.y << " ," << out.color << " ]" << std::endl;
  return os;
}

inline
std::istream& operator>> ( std::istream &is , const Line &in ) {
  std::cout<<"Line x , y , color info: " << std::endl;
  is >> in.x >> in.y >> in.color;
  return is;
}

int main(int argc, char *aargv) {
 Line new_line;
 std::cin>>new_line;
 std::cout<<new_line;
 return(0);
}

Am using g++ and on compiling i get the below errors, how to fix this
Code:
g++ friends.cpp
friends.cpp: In function `std::istream& operator>>(std::istream&, const Line&)   ':
friends.cpp:8: error: `int Point::x' is private
friends.cpp:34: error: within this context
friends.cpp:8: error: `int Point::y' is private
friends.cpp:34: error: within this context
friends.cpp:18: error: `int Line::color' is private
friends.cpp:34: error: within this context

Thanks
Nagarajan G
 

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ost::MapObject(3)					     Library Functions Manual						 ost::MapObject(3)

NAME
ost::MapObject - The MapObject is a base class which can be used to make a derived class operate on a MapTable. SYNOPSIS
#include <object.h> Public Member Functions void detach (void) Remove the object from it's current table. MapObject (const char *id) Save id, mark as not using any table. Protected Attributes MapObject * nextObject const char * idObject MapTable * table Friends class MapTable class MapIndex Detailed Description The MapObject is a base class which can be used to make a derived class operate on a MapTable. Derived classes may override new and delete operators to use managed free list from a MapTable. Author: David Sugar dyfet@gnutelephony.org Mappable object. Constructor &; Destructor Documentation ost::MapObject::MapObject (const char *id) Save id, mark as not using any table. Parameters: id string for this object. Member Function Documentation void ost::MapObject::detach (void) Remove the object from it's current table. Friends And Related Function Documentation friend class MapIndex [friend] friend class MapTable [friend] Member Data Documentation const char* ost::MapObject::idObject [protected] MapObject* ost::MapObject::nextObject [protected] MapTable* ost::MapObject::table [protected] Author Generated automatically by Doxygen for GNU CommonC++ from the source code. GNU CommonC++ Sat Jun 23 2012 ost::MapObject(3)
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