Sponsored Content
Top Forums Programming error: initializer expression list treated as compound expression Post 302145327 by arunchaudhary19 on Wednesday 14th of November 2007 12:00:40 AM
Old 11-14-2007
I dont know why it has occured .........
but when I compiled my program again after some time taking ....having some modifications in my code i.e collecting a return value of a function in a variable then this problem disappears....and my code working correctly....

but today when I again not collecting the return value of a function then also its working correctly...........

why so???????????
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

compound expression in unix

I am using the code below to write a command to launch a script only if the number of users on the system is less than 10. The code below isn't working. Any suggestions? HELP.. if && ; then frizzle ; fi (3 Replies)
Discussion started by: spalmer
3 Replies

2. Shell Programming and Scripting

Regular Expression + Aritmetical Expression

Is it possible to combine a regular expression with a aritmetical expression? For example, taking a 8-numbers caracter sequece and casting each output of a grep, comparing to a constant. THX! (2 Replies)
Discussion started by: Z0mby
2 Replies

3. Shell Programming and Scripting

One more expression syntax error

HI again, still working on the assignment, which is really hard given we just started unix 4 weeks ago. This script should change the permission for the user depending if its x, w or r, to the opposite. When i try to run it, I am getting expression error. Can you spot where the problem is? I really... (3 Replies)
Discussion started by: morava
3 Replies

4. Shell Programming and Scripting

Error with Expression

Hi All, am trying to add two Inputs i.e., $1 and $2, Code #!/bin/sh $num_sum=`expr $1+$2` echo "Sum = $num_sum" am giving statement sh arithemetic.sh 20 10 am getting error arithemetic.sh: line 2: =20+10: command not found Sum = I want Output as Sum = 30, (5 Replies)
Discussion started by: sunnix
5 Replies

5. Shell Programming and Scripting

if expression syntax error

#! /bin/csh set umr=UMR foreach i ( `ls`) set file_nm=$i set bh_nm=`echo $file_nm | cut -d"_" -f2` if($bh_nm !=$umr) then { set bh_ext=`echo $file_nm | cut -d"_" -f4` set bh_num_nm="$bh_nm $bh_ext a .txt" mv $file_nm $bh_num_nm } ... (1 Reply)
Discussion started by: jdsignature88
1 Replies

6. Shell Programming and Scripting

Integer expression expected: with regular expression

CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error. source $CA_VERSION_DATA if * ] then echo "CA_RELESE $CA_RELEASE is invalid" exit -1 fi + source /etc/ncgl/ca_version_data ++ CA_PRODUCT_ID=samxts ++ CA_RELEASE=6 ++ CA_WEEK_NO=7 ++... (3 Replies)
Discussion started by: ketkee1985
3 Replies

7. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

8. Shell Programming and Scripting

Getting error in this expression: value of value

HI , I have a variable "TYPE" which may contain different values. and another variable $TYPE"_SOURCE" I am using ${$TYPE"_SOURCE"} to get the value TYPE_SOURCE for eg. TYPE=ABC ABC_SOURCE=/abc/xyz On using above command I am getting error : BAD SUBSTITUTION eval is not installed... (2 Replies)
Discussion started by: aashish.sharma8
2 Replies

9. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies

10. Shell Programming and Scripting

Why Relational Expression is Writing to a Expression?

Hello All, Not sure why this is happening... When the following If Statement is evaluated for some reason it is creating a file in the CWD called '0'. I've seen this happen before, just not in an If Statement... CODE: if then DIR_NAME="$1" DIR_SIZE=0 STATUS="" else... (3 Replies)
Discussion started by: mrm5102
3 Replies
REGEXP(6)							   Games Manual 							 REGEXP(6)

NAME
regexp - regular expression notation DESCRIPTION
A regular expression specifies a set of strings of characters. A member of this set of strings is said to be matched by the regular expression. In many applications a delimiter character, commonly bounds a regular expression. In the following specification for regular expressions the word `character' means any character (rune) but newline. The syntax for a regular expression e0 is e3: literal | charclass | '.' | '^' | '$' | '(' e0 ')' e2: e3 | e2 REP REP: '*' | '+' | '?' e1: e2 | e1 e2 e0: e1 | e0 '|' e1 A literal is any non-metacharacter, or a metacharacter (one of .*+?[]()|^$), or the delimiter preceded by A charclass is a nonempty string s bracketed [s] (or [^s]); it matches any character in (or not in) s. A negated character class never matches newline. A substring a-b, with a and b in ascending order, stands for the inclusive range of characters between a and b. In s, the metacharacters an initial and the regular expression delimiter must be preceded by a other metacharacters have no special meaning and may appear unescaped. A matches any character. A matches the beginning of a line; matches the end of the line. The REP operators match zero or more (*), one or more (+), zero or one (?), instances respectively of the preceding regular expression e2. A concatenated regular expression, e1e2, matches a match to e1 followed by a match to e2. An alternative regular expression, e0|e1, matches either a match to e0 or a match to e1. A match to any part of a regular expression extends as far as possible without preventing a match to the remainder of the regular expres- sion. SEE ALSO
awk(1), ed(1), sam(1), sed(1), regexp(2) REGEXP(6)
All times are GMT -4. The time now is 06:39 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy