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Top Forums Shell Programming and Scripting How to get files names passed to a script Post 302144417 by aigles on Thursday 8th of November 2007 02:45:34 AM
Old 11-08-2007
A possible solution is to remove the first parameter before filling the array:
Code:
param1=$1
shift
set -A Files -- "$@"

Jean-Pierre.
 

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XZDIFF(1)							     XZ Utils								 XZDIFF(1)

NAME
xzcmp, xzdiff, lzcmp, lzdiff - compare compressed files SYNOPSIS
xzcmp [cmp_options] file1 [file2] xzdiff [diff_options] file1 [file2] lzcmp [cmp_options] file1 [file2] lzdiff [diff_options] file1 [file2] DESCRIPTION
xzcmp and xdiff invoke cmp(1) or diff(1) on files compressed with xz(1), lzma(1), gzip(1), or bzip2(1). All options specified are passed directly to cmp or diff. If only one file is specified, then the files compared are file1 (which must have a suffix of a supported com- pression format) and file1 from which the compression format suffix has been stripped. If two files are specified, then they are uncom- pressed if necessary and fed to cmp(1) or diff(1). The exit status from cmp or diff is preserved. The names lzcmp and lzdiff are provided for backward compatibility with LZMA Utils. SEE ALSO
cmp(1), diff(1), xz(1), gzip(1), bzip2(1), zdiff(1) BUGS
Messages from the cmp(1) or diff(1) programs refer to temporary filenames instead of those specified. Tukaani 2009-07-05 XZDIFF(1)
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