10-22-2007
I'm by no means a Solaris expert, but it looks like you are falling for the "cron error number 1": cronjobs have no environment, as they inherit from init and init is notoriously poor. ;-))
When you log on to a system your environment is set (by $HOME/.profile, $HOME/.kshrc, etc.) and all the jobs you start from there will inherit this environment. If you let cron start a job it will inherit the environment from cron, which itself has inherited its from init - and this is (next to) empty. "Normal" commodities like set PATH-variables, etc. are a not there and chances are the commands you use in your script are simply not found.
bakunin
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LEARN ABOUT SUSE
starting
starting(7) Miscellaneous Information Manual starting(7)
NAME
starting - event signalling that a job is starting
SYNOPSIS
starting JOB=JOB INSTANCE=INSTANCE [ENV]...
DESCRIPTION
The starting event is generated by the Upstart init(8) daemon when a new instance of a job begins starting. The JOB environment variable
contains the job name, and the INSTANCE environment variable contains the instance name which will be empty for single-instance jobs.
init(8) will wait for all services started by this event to be running, all tasks started by this event to have finished and all jobs
stopped by this event to be stopped before allowing the job to continue starting.
This allows jobs to effectively insert themselves as dependencies of other jobs. The event is typically combined with the stopped(7) event
by services.
Job configuration files may use the export stanza to export environment variables from their own environment into the starting event. See
init(5) for more details.
EXAMPLE
A service that wishes to be running whenever another service would be running, started before and stopped after it, might use:
start on starting apache
stop on stopped apache
A task that must be run before another task or service is started might use:
start on starting postgresql
SEE ALSO
started(7) stopping(7) stopped(7) init(5)
Upstart 2009-07-09 starting(7)