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Full Discussion: Cut Question
Top Forums UNIX for Dummies Questions & Answers Cut Question Post 302140922 by samit_9999 on Tuesday 16th of October 2007 05:24:36 PM
Old 10-16-2007
Cut Question

Hi,

I have created a variable abc within my script which can have values as follows

abc = Ram,Iam
or it can be
abc = Uam
or it can be
abc = Sam,Tam,Pam

Basically it can have a max of 3 values , seperated by comma.

I want to assign these 3 values to 3 different variables
In case of example 3 abc = Sam,Tam,Pam
Var1=Sam
Var2=Tam
Var3=Pam

I tried using the cut command , it works for the above example but when
abc = Uam
It assigns Uam to Var1,Var2,Var3

Here is what i am doing
Var1=`echo "$abc" | cut -f 1 -d ","`
Var2=`echo "$abc" | cut -f 2 -d ","`
Var3=`echo "$abc" | cut -f 3 -d ","`

I am not sure what is wrong with the above code.

Please help!

Sam
 

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NAMESPACE(6)							   Games Manual 						      NAMESPACE(6)

NAME
namespace - name space description file DESCRIPTION
Namespace files describe how to construct a name space from scratch, an operation normally performed by the newns subroutine (see auth(2)) which is typically called by init(8). Each line specifies one name space operation. Spaces and tabs separate arguments to operations; no quotes or escapes are recognized. Blank lines and lines with # as the first non-space character are ignored. Environment variables of the form $name are expanded within arguments, where name is a UTF string terminated by white space, a /, or a $. The known operations and their arguments are: mount [-abc] servename old [spec] Mount servename on old. bind [-abc] new old Bind new on old. import [-abc] host "[remotepath]mountpoint Import remotepath from machine server and attach it to mountpoint. cd dir Change the working directory to dir. The options for bind, mount, and import are interpreted as in bind(1) and import(4). SEE ALSO
bind(1), namespace(4), init(8) NAMESPACE(6)
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