why awk does not work here? Post: 302135041

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

awk may work!

:) have you tried awk... and pipe the actual start and end dates in the directory you're looking for when i go through my directories and look for certain matching files thats what i do except I am not quite sure what you are asking for so I can't give an exact example awk -f script file |...

2. Shell Programming and Scripting

NEED HELP (AWK or anything that would work)

Hi guys, heres my first post..... Input.txt: <abc a="" b="" c="" > <error x="" y="" z="" /> </abc> <abc a="" e="" c="" > ...

3. Shell Programming and Scripting

awk -v -- Why doesn't my example work?

Hi. I've been playing around a bit. This isn't for any practical purpose-- it's really just a theoretical exercise. I wrote this little thing: foreach num ( 6 5 4 ) awk -v "number=$num" 'BEGIN{for(x=0;x<$number;x++) printf "-"; printf "\n"}' end I would expect the following output: ...

4. Shell Programming and Scripting

Awk: Can anyone tell me why this doesn't work?

If there exists a field in stdin, print it, otherwise, print hello..... These print nothing: cat /dev/null | awk '{if ( length > 0 ) print $1; else print "hello"}' cat /dev/null | awk '{if ( $1 ) print $1; else print "hello"}'But the scripts work if I run them directly in a terminal: ...

5. Shell Programming and Scripting

awk: assign variable with -v didn't work in awk filter

I want to filter 2nd column = 2 using awk $ cat t 1 2 2 4 $ VAR=2 #variable worked in print $ cat t | awk -v ID=$VAR ' { print ID}' 2 2 # but variable didn't work in awk filter $ cat t | awk -v ID=$VAR '$2~/ID/ { print $0}'

6. Shell Programming and Scripting

Parse file using awk and work in awk output

hi guys, i want to parse a file using public function, the file contain raw data in the below format i want to get the output like this to load it to Oracle DB MARWA1,BSS:26,1,3,0,0,0,0,0.00,22,22,22.00 MARWA2,BSS:26,1,3,0,0,0,0,0.00,22,22,22.00 this the file raw format: Number of...

7. HP-UX

awk don't work in hp-ux 11.11

Hello all! I have problem in hp-ux 11.11 in awk I want to grep sar -d 2 1 only 3 column, but have error in awk in hp-ux 11.11 Example: #echo 123 234 | awk '{print $2}' 123 234 The situattions in commands bdf | awk {print $5}' some... In hp-ux 11.31 - OK! How resolve problem

8. UNIX for Dummies Questions & Answers

Why does this awk statement work?

So, I have an awk statement that does a little filtering and formats the output conveniently. Here's what I had originally: <input> | awk -F "\t" 'BEGIN{OFS=","} {sub(" ","_",$2)} (NR == 1) || (substr($2,9,2) >= 19 && substr($2,1,7) == "2011-02") {print}' That did what I wanted, except that...

9. Shell Programming and Scripting

Why my awk doesn't work?

root@SDP_Wildcat_Pass-3-C1:~# cat /proc/driver/rtc rtc_time : 05:29:40 rtc_date : 2014-12-19 alrm_time : 01:51:53 alrm_date : 2014-12-20 alarm_IRQ : no alrm_pending : no update IRQ enabled : no periodic IRQ enabled : no periodic IRQ...

10. UNIX for Dummies Questions & Answers

This awk should work, shouldn't it?

Heyas Trying to parse a tempfile, but somehow i mess up. To my understand, this should work... Plain: tail -n1 out.tmp 1 81.5M 1 1066k 0 0 359k 0 0:03:52 0:00:02 0:03:50 359k I want to get the 81.5M, so i'd assume it'll be $2 for awk.... tail -n1 out.tmp | awk...

LEARN ABOUT LINUX

shtool-path

SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME

       shtool-path - GNU shtool command dealing with shell path variables

SYNOPSIS

       shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]

DESCRIPTION

       This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments.  It
       prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.

OPTIONS

       The following command line options are available.

       -s, --suppress
	   Supress output. Useful to only test whether a program exists with the help of the return code.

       -r, --reverse
	   Transform a forward path to a subdirectory into a reverse path.

       -d, --dirname
	   Output the directory name of str.

       -b, --basename
	   Output the base name of str.

       -m, --magic
	   Enable advanced magic search for ""perl"" and ""cpp"".

       -p, --path path
	   Search in path. Default is to search in $PATH.

EXAMPLE

	#   shell script
	awk=`shtool path -p "${PATH}:." gawk nawk awk`
	perl=`shtool path -m perl`
	cpp=`shtool path -m cpp`
	revpath=`shtool path -r path/to/subdir`

HISTORY

       The GNU shtool path command was originally written by Ralf S.  Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
       over into GNU shtool.

SEE ALSO

       shtool(1), which(1).

18-Jul-2008							   shtool 2.0.8 						SHTOOL-PATH.TMP(1)