08-30-2007
You may try this code:
#dt=21102004
read dt
let month="${dt:2:2}"
let month=$month*3-3
st="JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC"
echo "${dt:0:2}-${st:$month:3}-${dt:4:4}"
Regards
Sethu.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Okay, I have posted on here one other time and received very fast help, so I figured I'd post again.
Searched for awhile and couldn't find exactly what I'm looking for.
I am attempting to write a script that will search through a given directory, or search through the current directory, and... (10 Replies)
Discussion started by: cbo0485
10 Replies
2. Shell Programming and Scripting
Hi
I am having date as a string in DDMMYYYY format(07082008) in a variable say cdate. I want to Convert it into DD Month YYYY format(7 August 2008). Could someone help. Thanks in Advance. (2 Replies)
Discussion started by: rspk_praveen
2 Replies
3. Shell Programming and Scripting
I have a CSV file which I have to sort it by a field with DDMMYYYY format, since I'm not a unix specialist, how is the easiest way to do this?
Sample data
30062008,432120,A,5001,A,201,Z ,2,MXN
31092008,432121,B,4001,B,101,Z ,2,MXN
05112008,432122,C,2001,C,51,Z ,2,MXN... (2 Replies)
Discussion started by: martinezjorge
2 Replies
4. Shell Programming and Scripting
i have an variable mydate=2008Nov07
i want o/p as in variable mymonth=11 (i.e nov comes on 11 number month)
i want some command to do this for any month without using any loop.
plz help me (1 Reply)
Discussion started by: RahulJoshi
1 Replies
5. Shell Programming and Scripting
input :
20110730
20110730
20110731
20110731
20110801
20110801
20110801
20110813
20110815
01062011
01062011
OUTPUT : i need to sort this input in such a way so that the latest date comes first. (11 Replies)
Discussion started by: urfrnddpk
11 Replies
6. Shell Programming and Scripting
I have a bunch of logs where the timestamp hours, minutes, seconds and milliseconds all together without a visual delimiter, as below
123045000
I'd prefer to see more easier to read familiar format, as
12:30:45.000
I came up with this ugly
echo '123045000'|awk '{print... (2 Replies)
Discussion started by: migurus
2 Replies
7. Shell Programming and Scripting
I have the following perl one-liner to get yesterday's date, but I would like it in the form of dd-MMM-yy (for example: 01-JAN-12). Can someone alter the below code so I get the format I want? Also, could someone also give me a line for dd-Mmm-yy (for example 01-Jan-12)?
Code:
YEST=`perl -w... (3 Replies)
Discussion started by: thibodc
3 Replies
8. Shell Programming and Scripting
My requirement is:- there will be files at a location each day with the date format DDMMYYYY.
Novawise_Activity_Call_Notes_04022013.txt
Novawise_Activity_Inbound_04022013.txt
Novawise_Activity_Inbound_05022013.txt
Novawise_Activity_Call_Notes_05022013.txt... (8 Replies)
Discussion started by: djrulz123
8 Replies
9. UNIX for Advanced & Expert Users
How to convert mmm-yy to mm/dd/yyyy format in unix ?
example:
Jan-99 to 01/01/1999
Jan-00 to 01/01/2000
Jan-25 to 01/01/2025
Dec-99 to 01/12/1999
Dec-00 to 01/12/2000
Dec-25 to 01/12/2025
YY anything between 00-50 should be 2000-2050
YY anything between 51-99 should be 1951-1999
... (2 Replies)
Discussion started by: gksenthilkumar
2 Replies
10. Shell Programming and Scripting
Record:
Record1|Record2|Record3|Record4|Record5|DATE1|DATE2
Need to Check DATE1 & DATE2 is in DDMMYYYY format in a file.
records which not meet the date format DDMMYYYY extract to other file. (1 Reply)
Discussion started by: vivekn
1 Replies
LEARN ABOUT PHP
gregoriantojd
GREGORIANTOJD(3) 1 GREGORIANTOJD(3)
gregoriantojd - Converts a Gregorian date to Julian Day Count
SYNOPSIS
int gregoriantojd (int $month, int $day, int $year)
DESCRIPTION
Valid Range for Gregorian Calendar 4714 B.C. to 9999 A.D.
Although this function can handle dates all the way back to 4714 B.C., such use may not be meaningful. The Gregorian calendar was not
instituted until October 15, 1582 (or October 5, 1582 in the Julian calendar). Some countries did not accept it until much later. For exam-
ple, Britain converted in 1752, The USSR in 1918 and Greece in 1923. Most European countries used the Julian calendar prior to the Grego-
rian.
PARAMETERS
o $month
- The month as a number from 1 (for January) to 12 (for December)
o $day
- The day as a number from 1 to 31
o $year
- The year as a number between -4714 and 9999
RETURN VALUES
The julian day for the given gregorian date as an integer.
EXAMPLES
Example #1
Calendar functions
<?php
$jd = GregorianToJD(10, 11, 1970);
echo "$jd
";
$gregorian = JDToGregorian($jd);
echo "$gregorian
";
?>
SEE ALSO
jdtogregorian(3), cal_to_jd(3).
PHP Documentation Group GREGORIANTOJD(3)