08-27-2007
Quote:
Originally Posted by
baghera
And I also tried to run ahmedwaseem2000's program but I didn't get that to work either. I really sorry but I'm a real "noob" at this. But the help you are giving me are invaluable.
what is the error you are getting? its working perfectly fine for me. see below
3 is the (1 + 5 )/2=3
YOU NEED TO ASSIGN VALUE OF "INPUT" VARIABLE before running the code else it will give you the "division by zero in modulus" like run INPUT=4 before running the code.
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CHSH(1) User Commands CHSH(1)
NAME
chsh - change your login shell
SYNOPSIS
chsh [-s shell] [-l] [-u] [-v] [username]
DESCRIPTION
chsh is used to change your login shell. If a shell is not given on the command line, chsh prompts for one.
chsh is used to change local entries only. Use ypchsh, lchsh or any other implementation for non-local entries.
OPTIONS
-s, --shell shell
Specify your login shell.
-l, --list-shells
Print the list of shells listed in /etc/shells and exit.
-u, --help
Print a usage message and exit.
-v, --version
Print version information and exit.
VALID SHELLS
chsh will accept the full pathname of any executable file on the system. However, it will issue a warning if the shell is not listed in
the /etc/shells file. On the other hand, it can also be configured such that it will only accept shells listed in this file, unless you
are root.
EXIT STATUS
Returns 0 if operation was successful, 1 if operation failed or command syntax was not valid.
SEE ALSO
login(1), passwd(5), shells(5)
AUTHOR
Salvatore Valente <svalente@mit.edu>
AVAILABILITY
The chsh command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux July 2009 CHSH(1)