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Top Forums Shell Programming and Scripting Question about working with data to create new column Post 302133036 by scottzx7rr on Tuesday 21st of August 2007 03:52:32 PM
Old 08-21-2007
Question about working with data to create new column

Hello,

I am having a problem with the script I am using to create a column from two columns I have in my file. I am needing to take column 5 and subtract it from column 2 to create column 6. I have included the script I am using and the rawdata I am using.

Raw Data File:
20070701,000004627,encode,29898,13620

Script

####usage: ./date_comp.sh >>outputfilename
awk '{$6=$2-$5
len="%0"length($2)"d"
$6=sprintf(len,$6)
$1=$1
print
}' "file_name"


Thanks in Advance.
 

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DB2_FIELD_SCALE(3)							 1							DB2_FIELD_SCALE(3)

db2_field_scale - Returns the scale of the indicated column in a result set

SYNOPSIS
int db2_field_scale (resource $stmt, mixed $column) DESCRIPTION
Returns the scale of the indicated column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns an integer containing the scale of the specified column. If the specified column does not exist in the result set, db2_field_scale(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_SCALE(3)
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