Sponsored Content
Top Forums Shell Programming and Scripting Count the number of occurence of perticular word from file Post 302131382 by fazliturk on Friday 10th of August 2007 09:41:15 AM
Old 08-10-2007
Quote:
Originally Posted by kahuna
I don't think this works if the word is in the middle of a larger word.
Code:
$echo compoundwordinmiddle >inputfile      
$count1=`wc -w inputfile`                  
$count2=`sed s/word/" "/g inputfile |wc -w`
$echo $count1
1 inputfile
$echo $count2
2

yes you are right but if not this code is very simple
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

word count showing wrong number of lines

Hi , I am using SUN OS Version 5.6. I have a file that contains records of length 270. when I do 'set nu' in vi editor, I get the count as 86. whereas when I do "wc -l" on the command prompt, it shows the count as only 85. this is very strange. why would the 'wc' show 1 record less. The job... (3 Replies)
Discussion started by: tselvanin
3 Replies

2. UNIX for Dummies Questions & Answers

search& count for the occurence of a word

Greetings, I need to search and count all the occurences of a word in all the files in a directory. Any suggestions greatly appreciated. Thanks (1 Reply)
Discussion started by: skoppana
1 Replies

3. Shell Programming and Scripting

Count number of digits in a word

Hi all Can anybody suggest me, how to get the count of digits in a word I tried WORD=abcd1234 echo $WORD | grep -oE ] | wc -l 4 It works in bash command line, but not in scripts :mad: (12 Replies)
Discussion started by: ./hari.sh
12 Replies

4. Shell Programming and Scripting

finding the number of occurence of a word in a line

suppose i have this line abs|der|gt|dftnrk|dtre i want to count the number of "|" in this line.. how can i do that. plz help:confused: (9 Replies)
Discussion started by: priyanka3006
9 Replies

5. UNIX for Dummies Questions & Answers

Count number of occurences of a word

I want to count the number of occurences of say "200" in a file but that file also contains various stuff including dtaes like 2007 or smtg like 200.1 so count i am getting by doing grep -c "word" file is wrong Please help!!!!! (8 Replies)
Discussion started by: shikhakaul
8 Replies

6. Shell Programming and Scripting

Count the number of occurrences of the word

I am a newbie in UNIX shell script and seeking help on this UNIX function. Please give me a hand. Thanks. I have a large file. Named as 'MyFile'. It was tab-delmited. I am told to write a shell function that counts the number of occurrences of the ord “mysring” in the file 'MyFile'. (1 Reply)
Discussion started by: duke0001
1 Replies

7. UNIX for Dummies Questions & Answers

how to count number of times each word exist in a file

I'm trying to count the number of times each word in the file exist for example if the file has: today I have a lot to write, but I will not go for it. The main thing is that today I am looking for a way to get each word in this file with a word count after it specifying that this word has... (4 Replies)
Discussion started by: shnkool
4 Replies

8. Shell Programming and Scripting

Count number of character occurence but not from quotation marks

I have the following string: 31-01-2012, 09:42:37;OK;94727132638;"Mozilla/5.0 (Linux; U; Android 2.2.1)";3G;WAP;I need a script which is counting the occurrence of semicolons ( ; ) but exclude the ones from the quotation marks. In the string given as example there are 8 semicolons but the script... (3 Replies)
Discussion started by: calinlicj
3 Replies

9. Shell Programming and Scripting

How to find the number of occurence of particular word from a text file?

example: i have the following text file... i am very tired. i am busy i am hungry i have to find the number of occurence of a particular word 'am' from the text file.. can any one give the shell script for it (34 Replies)
Discussion started by: sheela
34 Replies

10. Programming

Python Count Number Of Occurence

Hello, I have a programming assignment to count number of occurrences of hours in particular file. Below is the code: fname = raw_input("Enter file name: ") if len(fname) < 1 : fname = "mbox-short.txt" largest = None fh = open(fname) counts = dict() test = list() for line in fh: ... (2 Replies)
Discussion started by: infinitydon
2 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:43 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy