How would I strip a date field? For example, if I have
TODAY defined as the following: TODAY=`date +"%m/%d/%y"`,
TODAY is assigned the value 11/01/03 on Nov 1, 2003
How would I strip the first 2 bytes? (11)?
Thank you in advance for the help. (6 Replies)
can anyone help me with stripping an absolute filepath? I did a search on this topic but didnt find anything but maybe I didn't look hard. Anyway, would really appreciate it if anyone could help me. I am a new unix user so this might be a simple issue but I am stuck, don't really understand the use... (4 Replies)
we are ftping zipped up files from the development server to the production server daily.The files are in this format filename.dat.20061231.12131.gz
I have to unzip the file (i can do that with gunzip) and then strip out the timestamp after the .dat extension.
I can do something like this
... (4 Replies)
Hi All;
Having a problem with a file..
the file contains the following data... (a snapshot)
1331F9E9DB7C2BB80EAEDE3A8F043B94,AL7 1DZ,M,50
186FDF93E1303DBA217279EC3671EA91,NG5 1JU,M,24
3783FFAF602015056A8CD21104B1AAAF,CH42 4NQ,M,17
It has 3 columns sepreated by a ,
the second column... (7 Replies)
I have a variable that has an absolute path for a file on my computer. This dynamically changes. Is there a way I can assign two new variables from that one?
variable: /Users/keith/Desktop/test/file.mov
1) filename - no path or extention ....so just....file
2) path no filename or... (3 Replies)
Hello, I am the CEO of Grand Tech Corporation. We are launching Linux NT and forgive me, but I do not know how to strip binaries down in Mandriva Linux. Can someone tell me a way to?:b: (2 Replies)
I'm using a shell script to get user input with this command:
read UserInput
I would then like to take the "UserInput" variable and strip out all of the following characters, regardless of where they appear in the variable or how many occurrences there are:
\/":|<>+=;,?*@
I'm not sure... (5 Replies)
hi,
how to I do this?
i="4.000"
if ; then
echo "smaller"
fi
how do I convert the "4.000" to 4?
Thanks! (4 Replies)
Discussion started by: h0ujun
4 Replies
LEARN ABOUT PHP
numfmt_set_pattern
NUMFMT_SET_PATTERN(3) 1 NUMFMT_SET_PATTERN(3)NumberFormatter::setPattern - Set formatter pattern
Object oriented style
SYNOPSIS
public bool NumberFormatter::setPattern (string $pattern)
DESCRIPTION
Procedural style
bool numfmt_set_pattern (NumberFormatter $fmt, string $pattern)
Set the pattern used by the formatter. Can not be used on a rule-based formatter.
PARAMETERS
o $fmt
-NumberFormatter object.
o $pattern
- Pattern in syntax described in ICU DecimalFormat documentation.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
numfmt_set_pattern(3) example
<?php
$fmt = numfmt_create( 'de_DE', NumberFormatter::DECIMAL );
echo "Pattern: ".numfmt_get_pattern($fmt)."
";
echo numfmt_format($fmt, 1234567.891234567890000)."
";
numfmt_set_pattern($fmt, "#0.# kg");
echo "Pattern: ".numfmt_get_pattern($fmt)."
";
echo numfmt_format($fmt, 1234567.891234567890000)."
";
?>
Example #2
OO example
<?php
$fmt = new NumberFormatter( 'de_DE', NumberFormatter::DECIMAL );
echo "Pattern: ".$fmt->getPattern()."
";
echo $fmt->format(1234567.891234567890000)."
";
$fmt->setPattern("#0.# kg");
echo "Pattern: ".$fmt->getPattern()."
";
echo $fmt->format(1234567.891234567890000)."
";
?>
The above example will output:
Pattern: #,##0.###
1.234.567,891
Pattern: #0.# kg
1234567,9 kg
SEE ALSO numfmt_get_error_code(3), numfmt_create(3), numfmt_get_pattern(3).
PHP Documentation Group NUMFMT_SET_PATTERN(3)