07-13-2007
Thank you!
Now I have a file with the content like this:
20070711172841 905994
20070711172822 905994
20070711171431 906608
20070711171412 906608
20070711171142 905994
20070711171140 905994
20070711171139 905994
20070711164813 905994
I would like to keep only one line where the second column is the same. But that line should be the most lastest entry (timestamp in 1st coloumn).
I tried command:
sort -u -k 2,2
but this keeps the oldest timestamp
I tought that -u suppress everything but the first match. The first match (that should be kept) should be :
20070711172841 905994
but my command magically keeps the oldest line:
20070711164813 905994
Could you please advise on why -u does not work as anticipated?
Thank you!
BearCheese
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LEARN ABOUT DEBIAN
gfcombine
GFCOMBINE(1) UserCommands GFCOMBINE(1)
NAME
gfcombine - combine a number of shares to form the original file
SYNOPSIS
gfcombine [-o OUTPUTFILE] INPUTFILE...
DESCRIPTION
Combine a set of files (as produced by gfsplit) to produce the original file by interpolating the shares on the commandline.
-o OUTPUTFILE
The name of the file to write out.
All INPUTFILEs should be called something.NNN where the .NNN is the share number. (The gfsplit tool will output files named appropriately).
The OUTPUTFILE if omitted will default to the name of the first INPUTFILE with the .NNN removed.
AUTHOR
Written by Daniel Silverstone.
REPORTING BUGS
Report bugs against the libgfshare product on www.launchpad.net.
COPYRIGHT
Copyright (C) 2006 Daniel Silverstone.
This is free software. You may redistribute copies of it under the terms of the MIT licence (the COPYRIGHT file in the source distribu-
tion). There is NO WARRANTY, to the extent permitted by law.
SEE ALSO
gfsplit(1), libgfshare(3), gfshare(7)
1.0.5 February 2006 GFCOMBINE(1)