I made a small change to a UNIX script. When I tried to run it I received the following message:
/bin/ksh: ^M: not found
/bin/ksh: ^M: not found
/bin/ksh: ^M: not found
As ^M is a non printing character, I don't know how to discover where it is missing. How can I correct thiis... (2 Replies)
Hello All,
I'm trying to parse through a file and display all the hidden characters, including all carriage and line returns. I usually use cat -v, but this doesn't display the carriage and line returns. Does anyone know how this can be done?
Thanks
Khoom (5 Replies)
Can anyone seem to know how to find out whether a UNIX text file has 'hidden' control characters?
Can I view them using 'vi' by some command line options?
If there are control characters in a text file which are invisible/hidden.. then how do I get rid of them?
Your intelletual answers are... (6 Replies)
Hello everybody.
Im really new in shell scripting. Im working with RedHat 4.
I have begin to do some scripts to test the posibilitys but Im fancing a disturbing problem.
some times the lines that I write add the return character or end-of-file ascii character to the command or argument tha... (2 Replies)
I know that cat -v will show me hidden characters in a file....
I for some reason seem to think that there's a bash command that will show me hidden characters in a variable in a script? Or am I just imagining it?
Thanks in advance (8 Replies)
I am completely new to perl programming. My father is helping me learn said programming language. However, I am stuck on one of the assignments he has given me, and I can't find very much help with it via google, either because I have a tiny attention span, or because I can be very very dense.
... (4 Replies)
Hello everyone.
When I copy some configuration settings string from MS_Word to putty from my personal pc to a remote machine, it appears that I copy some hidden symbols, which at first, cannot be seen and appear as hidden. Some java programs did not start, and after investigation I found that:
... (3 Replies)
Hello.
I use this command :
rsync -av --include=".*" --dry-run "$A_FULL_PATH_S" "$A_FULL_PATH_D"The data comes from the output of a find command.
And no full source directories are in use, only some files.
Source example... (2 Replies)
Hi. I'm getting the following hidden characters \uat the start of a string after I pass in variables from the command line. I only noticed this when I set -x in my KSH script. Can anybody tell me how this happens and how to remove them?
Many thanks.
+ STR=$'\uusername testuser1'
+ print... (12 Replies)
Discussion started by: user052009
12 Replies
LEARN ABOUT REDHAT
open
OPEN(1) Linux 1.x OPEN(1)NAME
open - start a program on a new virtual terminal (VT).
SYNOPSIS
open [-c vtnumber] [-s] [-u] [-l] [-v] [--] command command_options
DESCRIPTION
open will find the first available VT, and run on it the given command with the given command options, standard input, output and error are
directed to that terminal. The current search path ($PATH) is used to find the requested command. If no command is specified then the envi-
ronment variable $SHELL is used.
OPTIONS
-c vtnumber
Use the given VT number and not the first available. Note you must have write access to the supplied VT for this to work.
-s Switch to the new VT when starting the command. The VT of the new command will be made the new current VT.
-u Figure out the owner of the current VT, and run login as that user. Suitable to be called by init. Shouldn't be used with -c or -l.
-l Make the command a login shell. A - is prepended to the name of the command to be executed.
-v Be a bit more verbose.
-w wait for command to complete. If -w and -s are used together then open will switch back to the controlling terminal when the command
completes.
-- end of options to open.
NOTE
If open is compiled with a POSIX (Gnu) getopt() and you wish to set options to the command to be run, then you must supply the end of
options -- flag before the command.
EXAMPLES
open can be used to start a shell on the next free VT, by using the command:
open bash
To start the shell as a login shell, use:
open -l bash
To get a long listing you must supply the -- separator:
open -- ls -l
SEE ALSO login(1), doshell(8), switchto(1).
AUTHOR
Jon Tombs <jon@gtex02.us.es or jon@robots.ox.ac.uk>
-w idea from "sam".
19 Jul 1996 V1.4 OPEN(1)