Sponsored Content
Full Discussion: Command line args
Top Forums Programming Command line args Post 302119210 by blowtorch on Monday 28th of May 2007 10:42:12 PM
Old 05-28-2007
That is how the scanf family of functions works. Try another test:
Code:
#include<stdio.h>

int main(int argc, char *argv[]){
        char message[80];

        fscanf(stdin,"%s",message);
        fprintf(stdout,"%s\n",message);
}

If you run this, this is what you get:
Code:
# ./a.out
this is a test
this

This is how it is implemented. Anyway, if you want to copy the second argument (argv[2]) into the message string, just use strcpy, like this:
Code:
#include<stdio.h>
#include<string.h>

int main(int argc, char *argv[]){
        int anInteger;
        char message[80];

        sscanf(argv[1], "%d", &anInteger);
        strcpy(message,argv[2]);
        fprintf(stdout,"anInteger: %d\nmessage: %s\n",anInteger,message);
}

This works as you want it to:
Code:
# ./a.out 2 "this is a test"
anInteger: 2
message: this is a test

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

required command line args

Hello, How do I make a command line argument required using getopts? Thanks. (6 Replies)
Discussion started by: yoi2hot4ya
6 Replies

2. UNIX for Dummies Questions & Answers

command line args

I am trying to print command line arguments one per second. I have this while do echo "6" shift echo "5" shift echo "4" shift echo "3" shift echo "2" shift echo "1" shift done (2 Replies)
Discussion started by: skooly5
2 Replies

3. UNIX for Dummies Questions & Answers

command line args 2

I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want... (2 Replies)
Discussion started by: skooly5
2 Replies

4. Shell Programming and Scripting

How to retrieve command line args one by on.

Hi, I have to store all the command line arguments into an array. I have the following code. ********************** #! /bin/sh set -A arr_no_updates i=1 while do arr_no_updates=$($i) echo ${arr_no_updates} i=$(($i+1)) done**************** (1 Reply)
Discussion started by: little_wonder
1 Replies

5. Shell Programming and Scripting

How to send a function all command line args?

I have this code, I thought it would automatically know the args sent to script when called from shell. But it seems to not see any... main script: . args . errors . opt . clean dbfile="" opfile="" # calls function in script below chkarg #check commands (2 Replies)
Discussion started by: gcampton
2 Replies

6. Shell Programming and Scripting

problem with KSH script: command line args

Hi I am executing a KSH script by passing command line arguments example: Red Green Dark Red Blue when I am splitting the arguments by using " "(Space) as delimiter But the colour Dark Red is a single parameter. But it is getting splitted in between How to avoid this. Please help Also... (4 Replies)
Discussion started by: hemanth424
4 Replies

7. Shell Programming and Scripting

command line args in unix

Hi, i have a perl script named test.pl. It is executed as cat *.log|test.pl i need the complete command line args. I tried using basename $0 but im getting test.pl only but not cat *.log... Can anyone help me on this. Thanks in advance (3 Replies)
Discussion started by: niteesh_!7
3 Replies

8. Emergency UNIX and Linux Support

Cut | command line args

Hi, Can you please hint me how to achieve the below? Input: $./script.sh start 1 2 Internally inside the script i want to set a single variable with $2 and $3 value? Output: CMD=$1 ARGS=$2 $3 --VInodh (10 Replies)
Discussion started by: vino_hymi
10 Replies

9. Shell Programming and Scripting

Passing Command Line Args in a Single Variable?

Hello All, I have a Bash Script and an Expect script that together will SSH to another server and do some stuff there... From within the Bash Script I process the Command Line Arguments, which are Required Args and Optional Args. When I call the Expect script from the Bash Script, I pass... (4 Replies)
Discussion started by: mrm5102
4 Replies

10. Shell Programming and Scripting

Getopts how to handle missing '-' in command line args.

I'm using getopts to process command line args in a Bash script. The code looks like this: while getopts ":cfmvhs:t:" option; do case $option in c) operationMode="CHECK" ;; f) operationMode="FAST" ;; m) ... (6 Replies)
Discussion started by: gencon
6 Replies
fmt(1)							      General Commands Manual							    fmt(1)

NAME
fmt - format text SYNOPSIS
width] [file...] DESCRIPTION
The command is a simple text formatter that fills and joins lines to produce output lines of (up to) the number of characters specified in the width option. The default width is 72. concatenates the arguments. If none are given, formats text from the standard input. Blank lines are preserved in the output, as is the spacing between words. does not fill lines beginning with a period for compatibility with Nor does it fill lines starting with Indentation is preserved in the output and input lines with differing indentation are not joined (unless is used). can also be used as an in-line text filter for the command: reformats the text between the cursor location and the end of the paragraph. Options recognizes the following options: Crown margin mode. Preserve the indentation of the first two lines within a paragraph and align the left margin of each subsequent line with that of the second line. This is useful for tagged paragraphs. Split lines only. Do not join short lines to form longer ones. This prevents sample lines of code, and other such "formatted" text, from being unduly combined. Fill output lines to up to width columns. WARNINGS
The width option is acceptable for BSD compatibility, but it may go away in future releases. SEE ALSO
nroff(1), vi(1). fmt(1)
All times are GMT -4. The time now is 06:11 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy