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Full Discussion: Derive date from a calendar
Top Forums Shell Programming and Scripting Derive date from a calendar Post 302114664 by autouser123 on Tuesday 17th of April 2007 03:33:29 PM
Old 04-17-2007
Yes, In normal scenarios, my job run date is same as current date.
In such cases, I'm looking up for files which have current date in file name.

But, there are certain situations where my job preprocessing takes longer time and eventually current date is different than the job start date (run date).

If I go with current date, I may end up picking up wrong files.

That is the reason I was looking if any common possible appraoch is present.

I understand that I can look for files as soon as the job starts so that current date remains same. But, wanted to know if there is any way to query calendar and get date.
 

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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)
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