The above compares yesterdays file to todays and find deleted records.
Thanks very much for the help.
First, get used to using vB Codes when quoting either code or other's posts - it really makes it easier to read and would improve your chances of people pay attention to you posts.
Secondly, you really don't need to
OR
both of the above is redundant: you don't need to assign '1' reading the first file as you're just building the hash the values of the hash don't matter as long as there's a key/index in a hash.
and you don't need to 'arr[$1] != 1' as the sheer presence of a key in a hash is enough. you re-code the second piece for ease of reading/understanding as:
i would like to pass a variable to awk wherein the variable comes from external loop.
i tried this...
let x=0
until test $x -eq 32
do
cat file | awk '{ print $1 , "Number" , $($x) }' >> output
done
thanks, (4 Replies)
I am trying to pass 2 shell variable's ("START" and "END") define earlier in the script to this awk statement, but i can't seem to pass it on. PLs help.
set START = xxxx
set END = yyyy
set selected_file = `awk '/$START/,/$END/' filename` (24 Replies)
HI all,
some more mistery about AWK, I hope you can help me out:
1)
I have a normal ksh script and sometime I call awk command. I set some variables in the script and I would like to use them up within AWK as well. Unfortunately AWK seems to forget all the variable values outside of its own... (1 Reply)
Hi,
I have a shell script with an ambedded awk script.
i need to pass a script variable to the awk script.
Please help.
Thanks in advance
Himani (3 Replies)
Hello experts,
can I return a value from gawk to a shell script ?
My script as follows,
#Here I want the num value to shell script so that I can use later
gawk '
{
split($0,num,",");
print num
}'
gawk -v no=$number '{print no}'
file1
... (3 Replies)
Read parameter from a text file with one line which stored the date value like 20080831; below is the awk command I used
gawk -F, "{getline RunDate;print $RunDate" text file
When print $RunDate, it display 20080831
Would like to pass this variable to another script to use but not... (6 Replies)
I'm trying to store the response from a nawk command inside of a ksh script. The command is:
text=$(nawk -F: '$1 ~ /${imgArray}/ {print $2}' ${etcDir}/captions.txt)
From what I can tell, the imgArray variable is not being expanding when it is inside the single quote ('). Is there something I... (4 Replies)
I know this topic has been dealt with previously, but the solutions I've seen don't work for me apparently.
I need to pass a variable defined in the shell to one in awk:
$ echo $var1
3
$ cat aaa
aaa 1
bbb 2
ccc 3
ddd 4
eee 5I've tried this, without success:
$ awk... (2 Replies)
Does anyone know of a way to do something similar to this with awk and kill? I want to create the variable in awk and pass that variable to kill.
ps -ef | grep -i chromium | awk '{$2=x}' | kill -9 $x 2>/dev/null (9 Replies)
Hello,
May i please know how do i pass the shell variable to awk expression in the below script. It is returning null
#!/bin/bash
UNINUM=720922
UNINUM_DESC=`awk -F'|' -v UNINUM=$2 '/UNINUM/ {print $4}' datafile`
echo $UNINUM_DESC
datafile
4|First|720194|asdasdad
4|First|720735|asdasdsa... (8 Replies)