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Top Forums Shell Programming and Scripting Change of directory thru script Post 302112229 by Raghuram.P on Tuesday 27th of March 2007 12:08:26 AM
Old 03-27-2007
Hi,
Sometimes getting the directory name by using cut -c61- may lead to error like it may not get the directory name properly.
Try the following code to get the directory name and use your code like this
ls -l | grep ^d | cut -d: -f2 | sed 's/[0-9][0-9] //g'

x=0
#for tree in $( ls -l | grep "^d" | cut -c61- ) Instead of this use
for tree in $( ls -l | grep ^d | cut -d: -f2 | sed 's/[0-9][0-9] //g' )
do
x=`expr $x + 1`
echo "$x $tree"
done
echo "Enter the view number to set or 0 to another view or q to quit"
read answer
y=0

If my assumption is right this will solve your issue...
Thanks
Raghuram
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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