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Top Forums Shell Programming and Scripting Help in a Recursive date program!!!! Post 302112040 by cfajohnson on Saturday 24th of March 2007 03:34:14 PM
Old 03-24-2007
Quote:
Originally Posted by kumarsaravana_s
Can you please tell me how to append date of this format 032307 and 20070323 in the middle of the file name as show below and dynamically update it everyday.

You mean insert the date into the filename (append means to place at the end).
Quote:
TP_ccc_ddd_032307.txt
aa_bb_032307.dat
BP_dd_ee_032307.dat
BP_ff_gg_032307.xls
BP_xx_yy_20070323134501.dat

First you need to break the file name into its various parts: name, date and suffix:

Code:
file=TP_ccc_ddd_032307.txt
suffix=${file##*.}
name=${file%_*}
temp=${file%."$suffix"}
date=${temp#"$name"_}

Then you need to convert the date. You show two different formats, so two different conversion functions must be used. The first format is the ridiculous MMDDYY; the second, I assume, is YYYYMMDDHHMMSS.

To determine which format the date is in, check the length:

Code:
case ${#date} in
  6) six2date ;;
  14) fourteen2date ;;
esac

Then reassemble the filename and do the move:

Code:
newfile=${name}_$_DATE.$suffix
mv "$file" "$newfile"

Here are the other functions you will need:

Code:
monthname()
{
  case $1 in
    01) _MONTH=Jan ;;   02) _MONTH=Feb ;;
    03) _MONTH=Mar ;;   04) _MONTH=Apr ;;
    05) _MONTH=May ;;   06) _MONTH=Jun ;;
    07) _MONTH=Jul ;;   08) _MONTH=Aug ;;
    09) _MONTH=Sep ;;   10) _MONTH=Oct ;;
    11) _MONTH=Nov ;;   12) _MONTH=Dec ;;
  esac
}

six2date()
{
   temp=${1#??}
   year=$(( ${1%"$temp"} + 2000 )) ## Fix if last century is possible
   monthname "${temp%??}"
   day=${temp#??}
   _DATE=$_MONTH-$day-$year
}

fourteen2date()
{
   temp1=${1#????}
   year=${1%"$temp1"}
   temp2=${temp1#??}
   monthname ${temp1%"$temp2"}
   temp3=${temp2#??}
   day=${temp2%"$temp3"}
   _DATE=$_MONTH-$day-$year
}

 

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sttime(3)                                                   ShapeTools Toolkit Library                                                   sttime(3)

NAME
stMktime, stWriteTime - date and time handling SYNOPSIS
#include <config.h> #include <sttk.h.h> time_tstMktime (char *string); char*stWriteTime (time_t date); DESCRIPTION
stMktime scans the given string and tries to read a date and time from it. It understands various formats of date strings. The following is a list of all valid formats, optional parts in brackets. [Tue] Jan 5[,] [19]93 This includes the standard asctime(3) format. Jan 5 With no year given, the year defaults to the current year. [19]93/01/05 This notation requires month and day represented by exactly two digits. 5.1.[19]93 This is the usual German notation. 5.1. German notation referencing the current year. A certain time, given together with the date must always have the following form. hours:minutes[:seconds] Each of the fields must be an integer value within the proper range (hours: 0-23, minutes and seconds: 0-59). Values below 10 may be written as one digit numbers. The time value may be placed anywhere in the date string: at the beginning, at the end, or somewhere in the middle. Any amount of white- space may be given between a field of the time value and the separating colon. The time is always considered to be local time. stWriteTime generates a time string similar to asctime(3) from its date argument. SEE ALSO
asctime(3) BUGS
Time Zone Names within the time string (like `MET') are not handled properly. In most cases they will cause a failure. sttk-1.7 Thu Jun 24 17:43:35 1993 sttime(3)
All times are GMT -4. The time now is 12:48 PM.
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