Sponsored Content
Top Forums Shell Programming and Scripting replace word with using "sed" not work... Post 302108622 by happyv on Wednesday 28th of February 2007 12:10:18 AM
Old 02-28-2007
Quote:
Originally Posted by matrixmadhan
Code:
>sed 's;F0</Number>;F</Number>;g' file
<Number>11 20 03 22 23 21 91 00 F</Number>
<Number>12 20 03 20 99 21 91 20 F</Number>
<Number>10 21 03 21 78 21 92 27 F</Number>

i am not sure...is it my file is xml format, the sed command not work.

sed 's;F0</Number>;F</Number>;g' file

if I used below, it work
sed 's; <Number>11 20 03 22 23 21 91 00 0F</Number>; <Number>11 20 03 22 23 21 91 00 F</Number>;g' file


Anyway, my file with more than 10,000 line and it waste time to manual to put the <number> information into the script.

any idea?
 

8 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Can "sed" substitute word on a specific line?

Hello experts, I know line number of the word I want to replace. Can "sed" substitute word on a specific line? As well, can sed substitute words inside a specific patten. ex. <word>lalala</word> #replace anything between <word> and </word> minifish (2 Replies)
Discussion started by: minifish
2 Replies

2. Shell Programming and Scripting

Extract Part of a "Word", using AWK or SED????

I have been lurking on this forum for some time now and appreciate Everyone's help. I need to find a way to get the SystemID from this XML file. The file is much larger than just this one line but I can grep and get this line Printed. But really just need the "systemid". <test123: prefintem... (9 Replies)
Discussion started by: elbombillo
9 Replies

3. Shell Programming and Scripting

cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'

hi All, cat file_name | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g' Can this be done by using sed or awk alone (4 Replies)
Discussion started by: harshakusam
4 Replies

4. Shell Programming and Scripting

Interesting question - Search and replace the word after sign "="

Hi Guys, Req your help in searching and replacing the word that comes after equals(=) symbol I would like to replace the sting in bold with a string in variable. d=ABCDF8C44C22 # grep -i NIM_MASTERID ${_NIMINFO} export NIM_MASTERID=00CDF8C44C00 I'm looking to replace any word that... (4 Replies)
Discussion started by: ajilesh
4 Replies

5. Shell Programming and Scripting

awk command to replace ";" with "|" and ""|" at diferent places in line of file

Hi, I have line in input file as below: 3G_CENTRAL;INDONESIA_(M)_TELKOMSEL;SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL My expected output for line in the file must be : "1-Radon1-cMOC_deg"|"LDIndex"|"3G_CENTRAL|INDONESIA_(M)_TELKOMSEL"|LAST|"SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL" Can someone... (7 Replies)
Discussion started by: shis100
7 Replies

6. Shell Programming and Scripting

how to use "cut" or "awk" or "sed" to remove a string

logs: "/home/abc/public_html/index.php" "/home/abc/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" how to use "cut" or "awk" or "sed" to get the following result: abc abc xyz xyz xyz (8 Replies)
Discussion started by: timmywong
8 Replies

7. Shell Programming and Scripting

How do i replace a word ending with "key" using awk excpet for one word?

echo {mbr_key,grp_key,dep_key,abc,xyz,aaa,ccc} | awk 'gsub(/^|abc,|$/,"") {print}' Required output {grp_key,xyz,aaa,ccc} (5 Replies)
Discussion started by: 100bees
5 Replies

8. Shell Programming and Scripting

Add the word "prefix" to beginning of line using sed

SUSE linux bash shell this works test -d /tmpp && echo "directory exists" || echo "directory doesn't exists" |sed -e "s/^/prefix /" prefix directory doesn't exists but why doesn't this work? test -d /tmp && echo "directory exists" || echo "directory doesn't exists" |sed -e... (3 Replies)
Discussion started by: snoman1
3 Replies
SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
All times are GMT -4. The time now is 12:03 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy