02-20-2007
Quote:
Originally Posted by srirams
Yes , I saw that ....
I am not able to understand how this datecalc can be included with our needs
You copy the datacalc script to your system.
From with in you script you next can call this script like you call any other command or script.
Again, Suppose your most recent log file is from Jan 28, 2007
In your script:
JDATE=`<path to location of datacalc>/datacalc -j 2007 01 28`
The variable JDATE will now hold the Julian Date representation of Jan 28, 2007.
A Julian date is a single number
Next you substract the 60 day.
((JDATE=${JDATE}-60))
You connvert the Julian Date back to the regualar date format
REGDATE=`<path to location of datacalc>/datacalc -j ${JDATE}`
The variable REGDATE will now hold the string "2006 11 29"
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LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)
cal_from_jd - Converts from Julian Day Count to a supported calendar
SYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)