I need to execute command at remote host from my program.
there is rs6000/aix standard command called rexec.
unfortunately rexec ask username and password which must supplied interactively, of course it is impossible runned by program.
So I have to change rexec command format to make user-name... (5 Replies)
Hi all,
I upgraded my SUSE 6.1 to SUSE 7.1 and at once the following things won't work anymore:
1) My DHCP client is not able anymore to retrieve my IP address from the @home server. It times out all the time. If I use a fixed IP I can get on the net, so there is no physical problem.
2) I... (3 Replies)
guys, need your help~~~~
I am setting up a Sun Enterprise 450 Ultra 4 server
originally I was using Sun solaris 9 1202 version.
but after an accident (i guess becoz i deleted something wrongly), the system cannot boot up.
and now I wana install a FreeBSD(since it is free and it will... (3 Replies)
I've still a little problem with sed.
So, the content of my file.txt is like:
101.10.20.2.1079 > 101.11.2.20.80:
101.10.20.2.1080 > 101.11.2.20.80:
101.10.20.2.1081 > 101.10.20.2..80:
101.05.15.143.1068 > tpo68-96-22-1.no.no.cox.net.4391:
101.05.15.143.1072 >... (5 Replies)
Hi all,
I've got a thorny sed/regex problem and I thought somebody out there might be able to help.
I'd like to use sed in a Makefile to parse a path string. The path might look like this:
case 1: /mnt/users/bob/build/src
or
case 2: /mnt/users/bob/build/src/foo
or
case 3: ... (4 Replies)
Surely there's an easier way to do this, lets see if anyone knows! I am new to scripting so go easy on me!
I have the following script and at the moment it doesn't work and I believe the problem is that I am using a while loop within a while loop. When I run the script using sh -x I can see... (6 Replies)
Hello does anyone know how to do the following using some simple unix if possible:
I have a file with the following info as comma separated. It shows username, id number and all the subjects they are enrolled in on the one line. The subjects are separated by colons.
UserName,ID,Subject... (13 Replies)
Good day,
I am trying to run a ssh command on a remote server, but when I run the command the server takes FOREVER... and ends up giving me an error..
then the script also kicks server load up by 100% while it is running..
But if I run the same command on the server it goes pretty quickly and... (3 Replies)
Hi,
I am new to shell scripting, but doing my best to learn things. Today doing courses there was exercise like this:
#!/usr/bin/bash
a=$1
b=$2
if ]
then
echo "Conditions are met"
else
echo "Conditions are not met"
fi
I improved it a little, beacuse of curiosity :D to this:
... (8 Replies)
Discussion started by: Rosentine
8 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)