Sponsored Content
Top Forums UNIX for Advanced & Expert Users given a date,find the next date Post 302098931 by Perderabo on Thursday 7th of December 2006 11:32:04 AM
Old 12-07-2006
This is a very common mistake. It is amazing how lucky we were that the year 2000 happened to be a leap year. 1900 and 2100 are far enough away from the current date that we often get away with it. It will be interesting to see how much stuff breaks in the year 2100. Smilie
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

How to find Previous date and Coming date

Hi All, How to find a date which is 7 days from the current date as well as how to find a date which is 7 days before this current date. Urgently i need help. Thanks in Advance Regards Arunava (2 Replies)
Discussion started by: arunava_maity
2 Replies

2. Shell Programming and Scripting

Find julian date for given corresponding date

Hi, is there any possibility to find julian date for given corresping date. I will be gladfull if i get it. Requirement : Input : 10 09 2006 output: julian date: 283 thanks srikanth (2 Replies)
Discussion started by: srikanthus2002
2 Replies

3. UNIX for Advanced & Expert Users

date issue-find prevoius date in a patricular format

Hi , I have written a shell script that takes the current date on the server and stores it in a file. echo get /usr/home/data-`date '+%Y%d'`.xml> /usr/local/sandeep/GetFILE.ini I call this GetFILE.ini file from an sftp program to fetch a file from /usr/home/ as location. The file is in... (3 Replies)
Discussion started by: bsandeep_80
3 Replies

4. Shell Programming and Scripting

How to find a date which is 7 days past when given current date

hii all. I have to get the date of the 7th day past from the current date. if i give the current date as sep 3 then i must get the date as 27th of august. can we get the values from the "cal" command. cal | awk '{print $2}' will this type of command work. actually my need is if today is... (17 Replies)
Discussion started by: ladtony
17 Replies

5. Shell Programming and Scripting

Date One Week Ago From Given Date, Not From Current Date

Hi all, I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date. So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was... (4 Replies)
Discussion started by: Donkey25
4 Replies

6. Shell Programming and Scripting

Converting a date to friday date and finding Min/Max date

Dear all, I have 2 questions. I have a file with many rows which has date of the format YYYYMMDD. 1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too. 2. After converting the date to... (10 Replies)
Discussion started by: 2001.arun
10 Replies

7. Shell Programming and Scripting

Find week of the year for given date using date command inside awk

Hi all, Need an urgent help on the below scenario. script: awk -F"," 'BEGIN { #some variable assignment} { #some calculation and put values in array} END { year=#getting it from array and assume this will be 2014 month=#getting it from array and this will be 05 date=#... (7 Replies)
Discussion started by: vijaidhas
7 Replies

8. UNIX for Dummies Questions & Answers

Find the count of files by last created date based on the given date range

My unix version is IBM AIX Version 6.1 I tried google my requirement and found the below answer, find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20" But newer command is not working in AIX version 6.1 unix I have given my requirement below: Input: atr files: ... (1 Reply)
Discussion started by: yuvaa27
1 Replies

9. Shell Programming and Scripting

Date: invalid date trying to set Linux date in specific format

i try to set linux date & time in specific format but it keep giving me error Example : date "+%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01" or date +"%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01" keep giving me this error : date: invalid date ‘19-01-2017 00:05:01' Please use CODE tags... (7 Replies)
Discussion started by: umen
7 Replies

10. Answers to Frequently Asked Questions

Compare date in .txt with system date and remove if it's lesser than system date

I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
All times are GMT -4. The time now is 12:49 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy