I have the following error:
ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }'
Syntax Error The source line is 1.
The error context is
BEGIN >>> NR <<< > 1 { print $2, $9 }
awk: 0602-500 Quitting The source line is 1.
What I want to do is ls a directory, skip the first... (3 Replies)
Hello,
I have the following command that does 2 searches.
awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE
How do I search up after the first search?
thanks (4 Replies)
i have a little awk script that I use looks this:
awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled.
i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled.... (2 Replies)
I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text.
Can anyone provide some assistance.
Thanks!! (4 Replies)
How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06
4.35109e+06
4.36134e+06
4.4535e+06
5.47752e+06
5.48777e+06
7.52554e+06
7.73036e+06
9.06158e+06
:confused: thank you (3 Replies)
Can anyone help with this this one liner:
nawk -v RS='' '$1=$1' InputFile
What I have in the file:
0.0013985457223116
-0.0002338180925628
0.0
0.0003709430584958
-0.0005763523138347
0.0
And the output I want:
0.0013985457223116 -0.0002338180925628 0.0
0.0003709430584958... (1 Reply)
I have a script problem that I am not able to solve due my very limited understanding of unix/awk.
This is the contents of test.sh
awk '{print $1}'
From the prompt if I enter:
./test.sh Hello World
I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
im using ls -l | xargs | awk '{what ever files here}'
im trying to get something that looks like this... (7 Replies)
Hi Experts,
I am trying to get system output to capture inside awk , but not working:
Please advise if this is possible :
I am trying something like this but not working, the output is coming wrong:
echo "" | awk '{d=system ("date") ; print "Current date is:" , d }'
Thanks, (5 Replies)
Discussion started by: rveri
5 Replies
LEARN ABOUT FREEBSD
column
COLUMN(1) BSD General Commands Manual COLUMN(1)NAME
column -- columnate lists
SYNOPSIS
column [-tx] [-c columns] [-s sep] [file ...]
DESCRIPTION
The column utility formats its input into multiple columns. Rows are filled before columns. Input is taken from file operands, or, by
default, from the standard input. Empty lines are ignored.
The options are as follows:
-c Output is formatted for a display columns wide.
-s Specify a set of characters to be used to delimit columns for the -t option.
-t Determine the number of columns the input contains and create a table. Columns are delimited with whitespace, by default, or with
the characters supplied using the -s option. Useful for pretty-printing displays.
-x Fill columns before filling rows.
ENVIRONMENT
The COLUMNS, LANG, LC_ALL and LC_CTYPE environment variables affect the execution of column as described in environ(7).
EXIT STATUS
The column utility exits 0 on success, and >0 if an error occurs.
EXAMPLES
(printf "PERM LINKS OWNER GROUP SIZE MONTH DAY " ;
printf "HH:MM/YEAR NAME
" ;
ls -l | sed 1d) | column -t
SEE ALSO colrm(1), ls(1), paste(1), sort(1)HISTORY
The column command appeared in 4.3BSD-Reno.
BUGS
Input lines are limited to LINE_MAX (2048) bytes in length.
BSD July 29, 2004 BSD