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Top Forums UNIX for Dummies Questions & Answers Hep with script to monitor directory Post 302094081 by mahendramahendr on Wednesday 25th of October 2006 04:25:28 AM
Old 10-25-2006
There are many ways in doing it... one is based on the time the file created in the system and the other way is based on date in the file name...

There will be a problem with the first method if the latest file ftp'd before the old files... old files will have latest file creation date than latest files and will move latest files to the archive folder...

Hence I adopted the second method which archives the file based on the date in the file name... hope this helps.

Code:
#!/usr/bin/ksh

for name in $(ls acme* | sed 's/_[0-9]*.txt//g' | uniq)
do
   cnt=0
   for fname in $(ls $name* | sed 's/_\([0-9][0-9]\)\([0-9][0-9]\)\([0-9][0-9]\)/_\3\1\2/g' | sort -r )
   do
      echo $fname
      nm=$(echo $fname | sed 's/_\([0-9][0-9]\)\([0-9][0-9]\)\([0-9][0-9]\)/_\2\3\1/g' )
      cnt=$(($cnt+1));
      if [ $cnt -ne 1 ]
      then
          mv $nm  ./bkup
          echo "$nm moved to backup"
      fi
   done
done

I have tested and it worked fine...
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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