I would like to create a script for calculating size and remaining space of a directory automatically every 24 hours, then send an email to report to the admin.
* POSIX and PERL are preferred.
Can anyone help, please? (1 Reply)
hello everybody!
I want to create a file with permissions for read, write, and execute to everybody using C, so I write this code:
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
int main(){
int fileDescriptor;
fileDescriptor =... (2 Replies)
hello dont know if this is the correct forum for this post but i have a question.
i am revising for a exam on operating systems and i have the question...
A system has a 32bit virtual address divided into 2kbyte pages and each entry in the page table is 6 bytes in length.
what is the size... (0 Replies)
Hi All,
I am very new to shell scripting. I have a text file which is the output of another utility. This text file has a list of SAF files which is basically a list of orphan attachments in the attachments directory. Now I want to read each file name from the file, get its size and repeat this... (6 Replies)
Hi,
from the manual
listen(2): listen for connections on socket - Linux man page
It has a parameter called backlog and it limits the maximum length of queue of pending list.
If I set backlog to 128, is it means no more than 128 packets can be handled by server?
If I have three... (3 Replies)
Hi
This is the lspv output of my server :
cbspsdb01 #lspv
hdisk0 00c7518d2d512fd4 cdgvg active
hdisk1 00c7518d2dcbc9d6 cdgvg active
hdisk2 00c7518dcda9199a appvg active
hdisk3... (1 Reply)
Hey guys.....
I have many files (lets say 100 or more) of same size, and I want to create a new output file and calculate the average of first row fifth column in all files and print it in first row of output file, then 2nd row fifth col in all 100 files and print it in 2nd row of output... (1 Reply)
hi everyone
i have a backup share mounted with me on solaris 10 which have daily backups. everyday i need to calculate all individual sizes of files and need to report somewhere. e.g i have .rman 7backup files daily . what i need that is there any commnd or variation of du command which can add... (1 Reply)
hi everyone
i have posted this query but i dont where it has gone
i am posting again . my issue is that i have many backup files in a backup nfs share and i need to calculate it size just by adding their individual file sizes which is repetitive jobs. so is there any command or variation of du... (1 Reply)
Discussion started by: janakors
1 Replies
LEARN ABOUT DEBIAN
parse_time
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL