Hello,
I create a file touch 1201093003 fichcomp
and inside a repertory (which hava a lot of files) I want to list all files created before this file :
find *.* \! -maxdepth 1 - newer fichcomp but this command returned bash: /usr/bin/find: Argument list too long
but i make a filter all... (1 Reply)
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.
Thanks in advance.
Regards
Jatin Jain (10 Replies)
I need to find whether there is a file named vijay is there or not in folder named "opt" .I tried "ls *|grep vijay" but it showed permission problem.
so i need to use find command (6 Replies)
Hello everyone,
first post here, trying to learn scripting on my own and this forum as been really helpful so far. I made few little scripts working great but I m facing some problems with RE.
I have a bunch of files in many subdirectories called *001.ext *002.ext OR simple *.ext or *01.ext... (7 Replies)
Hi all ,
I'm new to unix
I have a checked project , there exists a file called xxx.config .
now my task is to find all the files in the checked out project which references to this xxx.config file.
how do i use grep or find command . (2 Replies)
Hi Friends,
Please help me to sort out this problem, I am running this in centos o/s and whenever I run this script I am getting "find: missing argument to `-exec' " but when I run the same code in the command line I didn't find any problem. I am using perl script to run this ... (2 Replies)
I need assistance with following requirement, I am new to Unix.
I want to do the following task but stuck with file creation date(sysdate)
Following is the requirement
I need to create a script that will read the abc/xyz/klm folder and look for *.err files for that day’s date and then send an... (4 Replies)
Hello,
This is a bit complicated for me.
My scenario in MyFile:
Search string1,
When string1 is found, grep the line containing string1, go back over that line in upward direction and grep the first line containing string2.
Here is an example:
MyFile
His email address... (17 Replies)
Discussion started by: baris35
17 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)