09-28-2006
getting date from timestamp
Hi All,
i have a time stamp. from that i am trying to awk to get the year, month and date.
TIME=20060614092446
DESIRED OUTPUT: 20060614
i am doing the following;
TIME=20060614092446
$ TimeStarted=`expr match '$TIME' '.*\(......\)'`
echo $TimeStarted
i am not getting any output. can anyone please suggest me.
thanks
mark
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TIME(2) Linux Programmer's Manual TIME(2)
NAME
time - get time in seconds
SYNOPSIS
#include <time.h>
time_t time(time_t *t);
DESCRIPTION
time returns the time since the Epoch (00:00:00 UTC, January 1, 1970), measured in seconds.
If t is non-NULL, the return value is also stored in the memory pointed to by t.
RETURN VALUE
On success, the value of time in seconds since the Epoch is returned. On error, ((time_t)-1) is returned, and errno is set appropriately.
ERRORS
EFAULT t points outside your accessible address space.
NOTES
POSIX.1 defines seconds since the Epoch as a value to be interpreted as the number of seconds between a specified time and the Epoch,
according to a formula for conversion from UTC equivalent to conversion on the naive basis that leap seconds are ignored and all years
divisible by 4 are leap years. This value is not the same as the actual number of seconds between the time and the Epoch, because of leap
seconds and because clocks are not required to be synchronised to a standard reference. The intention is that the interpretation of sec-
onds since the Epoch values be consistent; see POSIX.1 Annex B 2.2.2 for further rationale.
CONFORMING TO
SVr4, SVID, POSIX, X/OPEN, BSD 4.3
Under BSD 4.3, this call is obsoleted by gettimeofday(2). POSIX does not specify any error conditions.
SEE ALSO
ctime(3), date(1), ftime(3), gettimeofday(2)
Linux 2.0.30 1997-09-09 TIME(2)