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Top Forums Shell Programming and Scripting Checking if string contains integer Post 302088205 by haz on Sunday 10th of September 2006 08:03:55 AM
Old 09-10-2006
Sorry, should have specified it is a Bourne shell script that I am writing.

This is what I've tried writing, where am i going wrong?

Code:
namenum=$1

if [ "$namenum" -eq *[a-zA-Z]* ] ; then
      echo "$namenum is all alphabetic"
else
      echo "not all alphabetic"
fi

 

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CTYPE_ALNUM(3)								 1							    CTYPE_ALNUM(3)

ctype_alnum - Check for alphanumeric character(s)

SYNOPSIS
bool ctype_alnum (string $text) DESCRIPTION
Checks if all of the characters in the provided string, $text, are alphanumeric. PARAMETERS
o $text - The tested string. RETURN VALUES
Returns TRUE if every character in $text is either a letter or a digit, FALSE otherwise. EXAMPLES
Example #1 A ctype_alnum(3) example (using the default locale) <?php $strings = array('AbCd1zyZ9', 'foo!#$bar'); foreach ($strings as $testcase) { if (ctype_alnum($testcase)) { echo "The string $testcase consists of all letters or digits. "; } else { echo "The string $testcase does not consist of all letters or digits. "; } } ?> The above example will output: The string AbCd1zyZ9 consists of all letters or digits. The string foo!#$bar does not consist of all letters or digits. NOTES
Note If an integer between -128 and 255 inclusive is provided, it is interpreted as the ASCII value of a single character (negative val- ues have 256 added in order to allow characters in the Extended ASCII range). Any other integer is interpreted as a string contain- ing the decimal digits of the integer. SEE ALSO
ctype_alpha(3), ctype_digit(3), setlocale(3). PHP Documentation Group CTYPE_ALNUM(3)
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