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Shell Programming and Scripting
Bourne Shell script - log for users loggin on and off
Post 302088028 by noodlesoup on Friday 8th of September 2006 05:27:45 AM
09-08-2006
Bourne Shell script - log for users logging on and off
Hello all, I'm new to shell scripting and want to make a script that I can write to log the users logging on and off the a unix system.
I have had a good look over the past few days to crack it, I think I am getting close.
I want a script that runs an infinite loop to check every 5 seconds to report on who logs into and who logs out of the unix system.
This is a example of the output I would like:
I am using
who | awk '{print $1}' | sort > temp1
to get the users logged on and saving that into a temp file.
and have a while loop set up like this which will run each 5 seconds.
while true
do
.
.
.
.
.
sleep 5
done
The problem I'm having is, I can't work out how to compare the current users logged in to the users that have previously logged in.
I thought of making a second temp file that stores the current users then using:
cmp temp1 temp2
to look at the difference. problem is it gives me an output saying "file differs at character 42, line 6" and that isn't helping me much as I would like to then display that users name but not sure how to print that position in the file (or just a line for that matter).
The test to see if the user has logged on or off is easy, as it is only a couple of if statements.
like if user is in temp1 but not in temp2 then the user has logged out and vice versa.
I have been looking at this for a while now and am going around in circles. any code fragments, help or written shell scripts
would be greatly appreciated.
Thanks in advance
Noodle
I have had a good look over the past few days to crack it, I think I am getting close.
I want a script that runs an infinite loop to check every 5 seconds to report on who logs into and who logs out of the unix system.
This is a example of the output I would like:
PHP Code:
The current users are:
abc1
rv0
sxu
tgray
No user has logged in/out in the last 5 seconds.
No user has logged in/out in the last 5 seconds.
User rsmith has logged in.
No user has logged in/out in the last 5 seconds.
User abc1 has logged out.
No user has logged in/out in the last 5 seconds.
who | awk '{print $1}' | sort > temp1
to get the users logged on and saving that into a temp file.
and have a while loop set up like this which will run each 5 seconds.
while true
do
.
.
.
.
.
sleep 5
done
The problem I'm having is, I can't work out how to compare the current users logged in to the users that have previously logged in.
I thought of making a second temp file that stores the current users then using:
cmp temp1 temp2
to look at the difference. problem is it gives me an output saying "file differs at character 42, line 6" and that isn't helping me much as I would like to then display that users name but not sure how to print that position in the file (or just a line for that matter).
The test to see if the user has logged on or off is easy, as it is only a couple of if statements.
like if user is in temp1 but not in temp2 then the user has logged out and vice versa.
I have been looking at this for a while now and am going around in circles. any code fragments, help or written shell scripts
would be greatly appreciated.Thanks in advance
Noodle
Last edited by noodlesoup; 09-08-2006 at 06:34 AM..
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LEARN ABOUT REDHAT
pam_console
pam_console(8) System Administrator's Manual pam_console(8) NAME
pam_console - control permissions for users at the system console SYNOPSIS
session optional /lib/security/pam_console.so auth required /lib/security/pam_console.so DESCRIPTION
pam_console.so is designed to give users at the physical console (virtual terminals and local xdm-managed X sessions by default, but that is configurable) capabilities that they would not otherwise have, and to take those capabilities away when the are no longer logged in at the console. It provides two main kinds of capabilities: file permissions and authentication. When a user logs in at the console and no other user is currently logged in at the console, pam_console.so will change permissions and own- ership of files as described in the file /etc/security/console.perms. That user may then log in on other terminals that are considered part of the console, and as long as the user is still logged in at any one of those terminals, that user will own those devices. When the user logs out of the last terminal, the console may be taken by the next user to log in. Other users who have logged in at the console during the time that the first user was logged in will not be given ownership of the devices unless they log in on one of the terminals; having done so on any one terminal, the next user will own those devices until he or she has logged out of every terminal that is part of the physical console. Then the race can start for the next user. In practice, this is not a problem; the physical console is not gener- ally in use by many people at the same time, and pam_console.so just tries to do the right thing in weird cases. ARGUMENTS
debug turns on debugging allow_nonroot_tty gain console locks and change permissions even if the TTY's owner is not root. permsfile=filename tells pam_console.so to get its permissions database from a different file than /etc/security/console.perms fstab=filename tells pam_console.so to read the table of configured filesystems from a file other than /etc/fstab when scanning permsfile. This file is used to map directories to device names. FILES
/var/run/console.lock /var/run/console/ /etc/security/console.apps /etc/security/console.perms SEE ALSO
console.perms(5) console.apps(5) /usr/doc/pam*/html/index.html pam_console_apply(8) /usr/doc/pam*/html/index.html BUGS
Let's hope not, but if you find any, please report them via the "Bug Track" link at http://bugzilla.redhat.com/bugzilla/ AUTHOR
Michael K. Johnson <johnsonm@redhat.com> Red Hat 2000/7/11 pam_console(8)