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Shell Programming and Scripting
KSH variable substitution
Post 302085033 by tmarikle on Monday 14th of August 2006 04:37:22 PM
08-14-2006
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Hello,
I thought it was possible to use several time a #! entry on a script but it doesn't seems to work. My need is to have a part of a ksh script without substitution so it would look like
#!/bin/ksh
--
first part
---
#!/bin/ksh -f
--
part without substitution
--
#!/bin/ksh
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Following code is working in bash but not in ksh.
Can someone please send me an alternative?
#!/bin/ksh
fname="EOA.dmp"
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echo $logname
I am getting below error in ksh
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Hi,
Following code is working in bash but not in ksh.
Can someone please send me an alternative?
#!/bin/ksh
fname="EOA.dmp"
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echo $logname
I am getting below error in ksh
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Hello,
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In bash I can use the following:
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the expected result is: 2
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ZGREP(1) General Commands Manual ZGREP(1) NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)