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Full Discussion: awk conditional statement
Top Forums Shell Programming and Scripting awk conditional statement Post 302083844 by mukundranjan on Tuesday 8th of August 2006 06:09:35 AM
Old 08-08-2006
Hi friend,

I have written below 2 line of code,
1. create a file with of diffrent value that we will use for testing.
2. Cat that file and check for the second parameter if it is greater than 30 then it will print 30. else it will print 00. You can put any value in place of other parameter.

Code:
1.  for((i=0;i<60;i++)); do echo "HH:$i:XX:YY:ZZ" >> tmp.txt; done
2. cat tmp.txt | awk -F":" '{ if($2<30) printf("%s:00:%s:%s:%s\n",$1,$3,$4,$5);} { if($2>30) printf("%s:30:%s:%s:%s\n",$1,$3,$4,$5);} '

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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