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Top Forums Shell Programming and Scripting Counting files in a directory that match a pattern Post 302080810 by Glenn Arndt on Thursday 20th of July 2006 04:18:03 PM
Old 07-20-2006
The "let 1 == 10" line is not setting 1 equal to 10. It is comparing 1 (the number of files it counted) and 10 (the number of files needed for success). Because 1 != 10, the script exits status 1, which is an error. The unix convention is that "0" is success, and anything else is failure.
 

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COMM(1) 						    BSD General Commands Manual 						   COMM(1)

NAME
comm -- select or reject lines common to two files SYNOPSIS
comm [-123f] file1 file2 DESCRIPTION
The comm utility reads file1 and file2, which should be sorted lexically, and produces three text columns as output: lines only in file1; lines only in file2; and lines in both files. The filename ``-'' means the standard input. The following options are available: -1 Suppress printing of column 1. -2 Suppress printing of column 2. -3 Suppress printing of column 3. -f Fold case in line comparisons. Each column will have a number of tab characters prepended to it equal to the number of lower numbered columns that are being printed. For example, if column number two is being suppressed, lines printed in column number one will not have any tabs preceding them, and lines printed in column number three will have one. comm assumes that the files are lexically sorted; all characters participate in line comparisons. EXIT STATUS
comm exits 0 on success, >0 if an error occurred. SEE ALSO
cmp(1), diff(1), sort(1), uniq(1) STANDARDS
The comm utility conforms to IEEE Std 1003.2-1992 (``POSIX.2''). BSD
June 6, 1993 BSD
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