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Top Forums Shell Programming and Scripting Problem with while loop in shell script Post 302080498 by reborg on Wednesday 19th of July 2006 08:05:31 AM
Old 07-19-2006
Code:
cat R2_20060719.610.txt | while read LINE
do
echo "$LINE"
done

or preferably
Code:
while read LINE
do
echo "$LINE"
done <R2_20060719.610.txt

Will not skip the last line, it will in effect behave exactly like the cat command. There are a number of ways you could aciehve the desired results. The simplest of which is probably to store the value of LINE in another variable, and print that value in the next iteration through the while loop.
 

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foo2zjs-pstops(1)					      General Commands Manual						 foo2zjs-pstops(1)

NAME
foo2zjs-pstops - Add PS code for foo2*-wrapper SYNOPSIS
foo2zjs-pstops [options] [file] DESCRIPTION
Add PS code for foo2zjs-wrapper. COMMAND LINE OPTIONS
These are the options that can appear on the command line. -a Accurate screens code. -c CIE Color. -n Neuter CUPS cupsPSLevel2 -r Rotate 90 degrees clockwise. -w Well Tempered Screens code. -D level Set Debug level [0]. FILES
/usr/bin/foo2zjs-pstops SEE ALSO
foo2hp2600-wrapper(1), foo2lava-wrapper(1), foo2oak-wrapper(1), foo2qpdl-wrapper(1), foo2slx-wrapper(1), foo2xqx-wrapper(1), foo2zjs-wrap- per(1) AUTHOR
Rick Richardson <rick.richardson@comcast.net> http://foo2zjs.rkkda.com/
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